Push a Block against a Wall- Static Friction

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SUMMARY

The discussion focuses on the physics problem of determining the normal force and acceleration of a block pushed against a wall with a horizontal force of 9 N. The block weighs 13 N, with a coefficient of static friction of 0.62 and kinetic friction of 0.42. The normal force exerted by the wall equals the push force, resulting in zero horizontal acceleration. The vertical forces, including gravity and friction, must be analyzed using Newton's laws to determine the block's actual acceleration.

PREREQUISITES
  • Understanding of Newton's laws of motion
  • Knowledge of static and kinetic friction coefficients
  • Ability to draw and interpret free body diagrams
  • Basic calculations involving force, mass, and acceleration
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  • Study the application of Newton's second law in two dimensions
  • Learn how to calculate normal force in various scenarios
  • Explore the implications of static vs. kinetic friction in real-world applications
  • Practice drawing free body diagrams for complex systems
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Students studying physics, particularly those focusing on mechanics, as well as educators looking for examples of static friction and force analysis in action.

Phoenixtears
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Homework Statement



A 9 N horizontal force F pushes a block weighing 13.0 N against a vertical wall (Fig. 6-21). The coefficient of static friction between the wall and the block is 0.62, and the coefficient of kinetic friction is 0.42. Assume that the block is not moving initially.


(Image attached)

Determine the normal force that the wall exerts against the block
9 N (It is the same amount pushing against the block- they should be equal)

Determine the blocks acceleration
m/s^2


Homework Equations



Fk= (Coefficient of K)*N
F=ma
Max= Push- normal
May= Static- mg

The Attempt at a Solution



Alright, I began drawing a force graph. On this graph weight faces down, normal force is exerted left (see attachement), static force is exerted up, and push force is exerted right. Determining the acceleration means horizontally, because the acceleration vertically is 9.8. Now, looking at my equations, only one contains 'a': F=ma. So, what do I know in this equation? I can get mass from the 13 N weight. 13/9.8= 1.32653 mass. That just leaves me to find the force. Going back, the acceleration I am trying to find is horizontal. So, I need to use the push-normal to get my total force. Here's my big problem, don't the push force and the normal force equal each other? So that would leave me with an Ma= 0. What does this mean? What have I done wrong?

Thank you in advance!

~Phoenix
 

Attachments

  • Block Against Wall.gif
    Block Against Wall.gif
    1.8 KB · Views: 1,253
Last edited:
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Hi Phoenixtears,

At this point I cannot view your attachment, but I can point out a couple of things about what you have written.

In the horizontal direction, if the two horizontal forces are equal and opposite, then they will give zero horizontal acceleration like you have found.

In the vertical direction, you seem to be assuming that the acceleration is 9.8m/s^2, which is not true. If an object is in free fall, its acceleration is 9.8m/s^2 downwards, but being in free fall means that gravity is the only force acting on it. However, here there are two forces in the vertical direction: gravity and the frictional force, so you have to use Newton's law to find out what the acceleration is.
 
Draw a free body diagram, if using the textbook knight. Otherwise draw a simple diagram and just as alphysicist suggested use Newtons Laws. You are asked for an acceleration but what direction is it in. Which way do you think it would go, imagine lightly holding a block up against a wall which way would it likely go?
 

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