Pushing a 6kg Pic Against a Wall: Find the Force Needed

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To prevent a 6kg picture from sliding against a wall, a force of 84N must be applied, calculated using the static friction coefficient of 0.7. The formula used is F = mg/U, where m is mass, g is gravitational acceleration, and U is the static friction coefficient. For the second scenario, where the force is applied at a 30-degree angle to the horizontal, the calculations would need to account for the angle's effect on the vertical and horizontal components of the force. The discussion emphasizes the importance of understanding free body diagrams in solving such physics problems. Overall, the key takeaway is the calculation of the necessary force to maintain static friction.
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i don't understand this..the way the forces go:frown:
if someone could show me how to do it and the steps..that would be great:
The static friction coefficient btw a wall and a pic is 0.7 while the kinetic one is 0.3. By what force shoudl one push the 6kg pic against the wall so that it will not slide?What if he/she pushed the pic with a force making an angle of 30 degrees to the horizontal (both cases)[?]


thanx!
 
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If you draw a freebody diagram, you will find that for the picture to not slide,
U*F=m*g
must be true. To solve for F:
F=mg/U
m=6kg
g=9.8m/s^2
U=.7
So F=84N
But I can't be sure because I don't know if I understand what you mean and I don't know what you mean by the second part of the question.
 
thanx for the help
i think i can take it from here :smile:
 
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