Putting rotating cylinder on the ground

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SUMMARY

The discussion centers on the dynamics of a rotating cylinder with a radius of 0.1m and an initial angular velocity of 10 revolutions per second, placed on horizontal ground. The coefficient of friction is 0.1, and the objective is to determine the time it takes for the cylinder to roll without slipping. The correct answer is established as 2.09 seconds, with clarification that the initial frequency provided was the standard frequency rather than angular frequency. Key equations utilized include F=ma and M=J ⋅ ∝.

PREREQUISITES
  • Understanding of rotational dynamics
  • Familiarity with the moment of inertia (J)
  • Knowledge of friction coefficients
  • Basic principles of angular motion
NEXT STEPS
  • Study the relationship between angular velocity and linear velocity
  • Learn about the dynamics of rolling motion
  • Explore the concept of moment of inertia in different shapes
  • Investigate the effects of varying coefficients of friction on motion
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Students in physics, mechanical engineers, and anyone interested in understanding the principles of rotational motion and friction dynamics.

srecko97
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Homework Statement


We put a cyllinder with unknown mass and radius 0.1m which rotates with angular velocity 10 /s around its geometric axis on the horizontal ground. After what time does the cyllinder roll without slipping? Coefficient of friction is 0.1.

Homework Equations


F=ma
M=J ⋅ ∝

The Attempt at a Solution


J- moment of inertia, k-coefficient of friction ... a* - acceleration of center of mass[/B]
image.jpg


image.jpg

The result should be 2.09 s. Please correct me!
 
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Are you sure you've stated the problem correctly? Your answer looks right to me.
 
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I have just realized that everything is OK except the value for angular frequency. The given frequency is not the angular (which I thought) but the usual frequency (number of turns per second)
 
srecko97 said:
I have just realized that everything is OK except the value for angular frequency. The given frequency is not the angular (which I thought) but the usual frequency (number of turns per second)

Of course!
 
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