Putting rotating cylinder on the ground

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Homework Help Overview

The problem involves a rotating cylinder with an unknown mass and a specified radius, which is placed on horizontal ground. The discussion centers around determining the time it takes for the cylinder to roll without slipping, given a coefficient of friction.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • Participants discuss the relationship between angular velocity and the frequency provided, with some questioning the interpretation of the given frequency as angular rather than standard frequency.

Discussion Status

There appears to be a productive dialogue regarding the interpretation of the frequency and its implications for the problem. Some participants express confidence in the calculations, while others seek clarification on the initial problem statement.

Contextual Notes

Participants note potential confusion regarding the distinction between angular frequency and standard frequency, which may affect the understanding of the problem setup.

srecko97
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Homework Statement


We put a cyllinder with unknown mass and radius 0.1m which rotates with angular velocity 10 /s around its geometric axis on the horizontal ground. After what time does the cyllinder roll without slipping? Coefficient of friction is 0.1.

Homework Equations


F=ma
M=J ⋅ ∝

The Attempt at a Solution


J- moment of inertia, k-coefficient of friction ... a* - acceleration of center of mass[/B]
image.jpg


image.jpg

The result should be 2.09 s. Please correct me!
 
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Are you sure you've stated the problem correctly? Your answer looks right to me.
 
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I have just realized that everything is OK except the value for angular frequency. The given frequency is not the angular (which I thought) but the usual frequency (number of turns per second)
 
srecko97 said:
I have just realized that everything is OK except the value for angular frequency. The given frequency is not the angular (which I thought) but the usual frequency (number of turns per second)

Of course!
 
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