Questions on Convergence of Sequence {an}: Find Its Limits

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The sequence {an} is defined recursively, starting with a1=1 and following the rule an+1=√(1+an/2). To determine convergence, it is suggested to analyze the behavior of the sequence by calculating initial terms, which appear to be increasing. The discussion highlights the importance of applying theorems related to the convergence of increasing sequences. To find the limit, one should take the limit of both sides of the recursive equation, leading to a solvable equation for the limit value. The convergence and limit of the sequence can thus be established through these mathematical principles.
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The sequence {an} is defined by

a1=1,an+1=\sqrt{1+an/2} ,n=1,2,3,4,...

(a) a^2n-2<0 , (b)a^2a+1-a^2n>0. deduce that{an} converges and find its limits?

please help me get the answer...
 
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Are the (a) and (b) a^{2n-2} and a^{2n-1}- a^{2n}&gt; 0? If so, what is "a" and what do they have to do with the given sequence?

Have you never seen any sequences like this before?? You don't seem to have even tried anything. While looking at a few terms won't prove anything, it might help you see what's happening: a_1= 1, a_2= \sqrt{1+ 1/2}= \sqrt{3/2}, a_3= \sqrt{1+ \sqrt{3/2}/2}= \sqrt{(2+ \sqrt{3/2})/2}. Does that look like it is increasing? Do you know any theorem about convergence of increasing sequences?

As for finding the limit, what happens if you take the limit on both sides of the equation a_{n+1}= \sqrt{1+ a_n/2}?
 
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