- #1
roam
- 1,271
- 12
Homework Statement
The following is part of a solution to a problem about finding equiblirum points of a differential equation and sketching its bifurcation diagram
http://img32.imageshack.us/img32/9194/63226925.jpg
How did they get [itex]y= -1 \pm \sqrt{1- \mu}[/itex]?
Homework Equations
The quadratic equation:
[itex]\frac{-b \pm \sqrt{b^2-4ac}}{2a}[/itex]
The Attempt at a Solution
Setting the DE equalt to 0:
[itex]\frac{dy}{dt} = \mu +2y+y^2 = 0[/itex]
Using the quadratic formula:
[itex]y = \frac{-2 \pm \sqrt{4-4 \mu}}{2}[/itex]
[itex]= -1 \pm \frac{\sqrt{4-4 \mu}}{2}[/itex]
So how did they get that answer? Any explanation is appreciated.
Last edited by a moderator: