Quantum Mechanics algebra - complex analysis

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Homework Help Overview

The discussion revolves around the application of complex analysis in quantum mechanics, specifically focusing on the manipulation of real and imaginary parts of complex functions. The original poster seeks clarification on the workings shown in a provided image related to this topic.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the relationship between complex exponentials and trigonometric functions, particularly how taking the imaginary part simplifies certain integrals. Questions arise regarding specific steps in the working shown and the implications of manipulating these parts.

Discussion Status

There is an ongoing exploration of the concepts involved, with some participants providing insights into the properties of imaginary parts of complex numbers. However, there is no explicit consensus on the original poster's confusion regarding the last steps of the working.

Contextual Notes

The original poster references an attached image that is not visible in the discussion, which may limit the clarity of the conversation. Additionally, the discussion touches on the complexities of integrating functions involving complex numbers.

sxc656
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Hi,

I cannot work out how the working shown in the attached pic is well, er worked out!:confused:
Could someone explain the ins and outs of the complex analysis of taking the real or imaginary parts of some formula, for example in the context of the my case.
 

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Remember that e^{ix}= cos(x) + isin(x). Taking the imaginary part means you're looking at just the sine part. When you combine into that integral form, the solution is simpler.
 
Pengwuino said:
Remember that e^{ix}= cos(x) + isin(x). Taking the imaginary part means you're looking at just the sine part. When you combine into that integral form, the solution is simpler.

Is this what you mean, i am not sure about the last two lines of working.
 

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You can write

sin pr = Im(e^{ipr})

Because Im(z+w) = Im(z)+Im(w) and Im(az) = aIm(z) for real a, you can pull the other exponential in as well as reverse the order of I am and the integral.
 
Thanks to all:approve:
 

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