- #1
Collisionman
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Homework Statement
Consider a system that is initially in the state:
[itex]\psi\left(\theta,\phi\right)=\frac{1}{\sqrt{5}}Y_{1,-1}\left(\theta,\phi\right) + \frac{\sqrt{3}}{5}Y_{1,0}\left(\theta,\phi\right)+\frac{1}{\sqrt{5}}Y_{1,1}\left(\theta,\phi\right)[/itex]
Part 1: Find [itex]<\psi|L_{+}|\psi>[/itex]
Part 2: If [itex]L_{z}[/itex] is measured, what values would one obtain and with what probabilities?
Homework Equations
- [itex]L_{z}|lm>=mh|lm>[/itex]
- [itex]L_{+}|lm>=[l(l+1)-m(m+1)]^{\frac{1}{2}}h|lm + 1>[/itex]
- [itex]Probability = \frac{|<\varphi|\psi>|^{2}}{<\psi|\psi>}[/itex]
The Attempt at a Solution
For Part 1:
So I started off by putting the expression for [itex]\psi\left(\theta,\phi\right)[/itex] in Bra-Ket notation:
[itex]|\psi> = \frac{1}{\sqrt{5}}|1,-1> + \frac{\sqrt{3}}{5}|1,0> + \frac{1}{\sqrt{5}}|1,1>[/itex]
Then I applied [itex]L_{+}[/itex] to each individual component:
- [itex]L_{+}|1,-1> = \frac{1}{\sqrt{5}}[1(1+1)-(-1)(-1+1)]^{\frac{1}{2}}h|1,0> = \sqrt{\frac{2}{5}}h|1,0>[/itex]
- [itex]L_{+}|1,0> = \frac{\sqrt{3}}{5}[1(1+1)-0(0+1)]^{\frac{1}{2}}h|1,1> = \frac{\sqrt{6}}{2}h|1,1>[/itex]
- [itex]L_{+}|1,1> = \frac{1}{\sqrt{5}}[1(1+1)-(-1)(-1+1)]^{\frac{1}{2}}h|1,2> = 0[/itex]
So, [itex]L_{+}|\psi> = \sqrt{\frac{2}{5}}h|1,0>[/itex][itex]+ \frac{\sqrt{6}}{2}h|1,1>[/itex]
And then,
[itex]<\psi|L_{+}|\psi> = <1,0|\sqrt{\frac{2}{5}}h|1,0>[/itex][itex]+ <1,1|\frac{\sqrt{6}}{2}h|1,1>[/itex]
As [itex]<1,1|1,1> = 1[/itex] and [itex]<1,0|1,0>=1[/itex]
[itex]<\psi|L_{+}|\psi> = \sqrt{\frac{2}{5}}h[/itex][itex]+ \frac{\sqrt{6}}{2}h[/itex]
I think I'm going wrong here somewhere. I think I'm using the wrong complex conjugate. Can someone verify if I am or not?
For Part 2:
I took [itex]\psi\left(\theta,\phi\right)[/itex] in Bra-Ket notation as before, i.e.,
[itex]|\psi> = \frac{1}{\sqrt{5}}|1,-1> + \frac{\sqrt{3}}{5}|1,0> + \frac{1}{\sqrt{5}}|1,1>[/itex]
And used [itex]L_{z}|lm>=mh|lm>[/itex] to try and obtain a value for [itex]L_{z}[/itex]. I used this on individual components as follows;
- [itex]L_{z}|1,-1> = \frac{-h}{\sqrt{5}}|1,-1>[/itex]
- [itex]L_{z}|1,0> = \frac{\sqrt{3}}{5}(0)h|1, 0> = 0[/itex]
- [itex]L_{z}|1,1> = \frac{h}{\sqrt{5}}|1,1>[/itex]
Then I multiplied by the complex conjugate, i.e.,
- [itex]<1,-1|L_{z}|1,-1> = <1,-1|\frac{-h}{\sqrt{5}}|1,-1>[/itex]
- [itex]<1,1|L_{z}|1,1> = <1,1|\frac{h}{\sqrt{5}}|1,1>[/itex]
So, [itex]L_{z}=[/itex][itex]\frac{-h}{\sqrt{5}}[/itex][itex] + \frac{h}{\sqrt{5}} = 0[/itex]
Again, I'm not too sure if I'm right or wrong here. If someone could verify if I am or not, I'd really appreciate it. If I know where I'm going with [itex]L_{z}[/itex] I can continue on with finding the probabilities, which I understand how to do.
Thanks again in advance. Any help appreciated!
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