Konte
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Hi everybody,
In Robert W. Boyd's book "Nonlinear Optics", the quantum treatment of the nonlinear optical susceptibility lead to the next expression, for the second order case:
\chi^{(2)}_{ijk}(\omega_{\sigma},\omega_q,\omega_p)=\frac{N}{\hbar^2} P_F\sum_{mn} \frac{\mu_{gn}^i\mu_{nm}^j\mu_{mg}^k}{(\omega_{ng}-\omega_{\sigma})(\omega_{mg}-\omega_p)}
- At first time, I supposed \mu_{nm}=\langle{\phi_n} |\hat{\mu} |{\phi_m}\rangle where \phi_n and \phi_m are eigenstates of nonperturbated system. But when I saw the illustration (the same that I show you here), the levels n and m are virtuals !
My question is: in concrete case, how to define and calculate the matrix element \mu_{nm} ?
Thank you everybody.
* forgive me for my English.
In Robert W. Boyd's book "Nonlinear Optics", the quantum treatment of the nonlinear optical susceptibility lead to the next expression, for the second order case:
\chi^{(2)}_{ijk}(\omega_{\sigma},\omega_q,\omega_p)=\frac{N}{\hbar^2} P_F\sum_{mn} \frac{\mu_{gn}^i\mu_{nm}^j\mu_{mg}^k}{(\omega_{ng}-\omega_{\sigma})(\omega_{mg}-\omega_p)}
- At first time, I supposed \mu_{nm}=\langle{\phi_n} |\hat{\mu} |{\phi_m}\rangle where \phi_n and \phi_m are eigenstates of nonperturbated system. But when I saw the illustration (the same that I show you here), the levels n and m are virtuals !
My question is: in concrete case, how to define and calculate the matrix element \mu_{nm} ?
Thank you everybody.
* forgive me for my English.