When we move a wire through a magnetic field appears a magnetic force that distributes loads at one end of the wire ( following equation F = q⋅(vxB) ), until an opposite force is generated on the wire by the electric field (E) caused by charge distribution. This causes the EMF or induced voltage. When we close the circuit the current flows thanks to the electric field… but what happens when the circuit is open? in real generators the wires are coils in which a sinusoidal emf is induced, which means that charges flow sinusoidally from one end to another of the wire without load. If the intensity is dQ / dt through a section of the wire, why no intensity? has to do with the magnetic field does no work nor affect the kinetic energy of the electrons ? This shift in load distribution generates power losses?