Question about chemical nomenclature

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Discussion Overview

The discussion revolves around the chemical nomenclature and structural isomerism of 1,3-dibromo-1,3-dimethylcyclobutane, specifically focusing on the existence of cis- and trans- forms. Participants explore the implications of molecular structure on nomenclature and stereochemistry.

Discussion Character

  • Technical explanation, Conceptual clarification

Main Points Raised

  • One participant inquires about the reasons for the existence of cis- and trans- forms of 1,3-dibromo-1,3-dimethylcyclobutane.
  • Another participant suggests that examining the 3D structures makes the distinction between cis and trans forms clear, indicating that trans is on the "other side" and cis is on the "same side."
  • A different participant reiterates the importance of 3D structures and notes that the molecule cannot rotate around the axis of the single bond.
  • One participant counters that the presence of two single bonds in the ring structure prevents rotation, implying that interconversion between the isomers requires breaking a bond or manipulating the methyl groups.
  • A later reply expresses understanding of the topic after the discussion.

Areas of Agreement / Disagreement

Participants present differing views on the implications of the molecular structure for rotation and interconversion between isomers, indicating that the discussion contains multiple perspectives and is not fully resolved.

Contextual Notes

The discussion does not clarify the specific assumptions regarding the rigidity of the cyclobutane ring or the definitions of cis and trans in this context.

yeung2743
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I want to know why there are cis- and trans form of 1,3dibromo-1,3-dimethylcyclobutane?

and anybody explain it to me thanks a lot
 
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If you look at the 3d structures it should be fairly obvious
Trans ("other side") to the right, cis (same side") to the left.
 

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Nemus said:
If you look at the 3d structures it should be fairly obvious
Trans ("other side") to the right, cis (same side") to the left.

and it can't rotate around the axis of the single bond
 
No, there are two single bonds locking it in a stiff ring so you either have to break a bond or squeeze a methyl group through the center of the ring to interconvert them.
 
I understand now
Thx all you three guys ^^
 

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