Question about integration shouldn't be too difficult

[AxiomOfChoice]

Really, I should know the answer to this, but...

Suppose I'm trying to perform an integration with respect to t:

<br /> \int_0^T f(\phi(t)) dt<br />

So my function f is explicitly a function of \phi, and \phi depends on time t. But then suppose I end up being able to write the integral as

<br /> \int_0^T g(\phi(t)) \frac{d \phi}{dt} dt.<br /> [/itex]<br /> <br /> Can I just cancel the dt and perform an integral with respect to \phi? If so, I need to change the limits of integration, right?

 

[csprof2000]

Yes, this is my understanding.

Example: Find the mass of a rod of length L and uniform mass density D.

M = integral of dm

D = dm/dx

so D dx/dm = 1 and

M = integral of (1 dm) = integral of (D dx/dm dm) = integral of(D dx)

Since you're now working in distance-space, you just switch the limit to the distance-space limit, namely, 0 -> L.

 

[yyat]

Also known as http://en.wikipedia.org/wiki/Integration_by_substitution" .