Question about Jet engines (thermodynamics)

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Maximilian Popelier
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Hi, I need help
I got a project for school about jet engines. They say bysubstitution of equations 5.1, 5.2, 5.5 and 5.6
butI don't know the steps how i get t0 the last formule.
jet engine.png

Thank you
Maximilian Popelier
 
on Phys.org
Take eq. (5.7) and replace ##w_a## and ##q_a## by the right-hand side of (5.5) and (5.6), and then further simplify using (5.1) and (5.2).
 
Tank you very much i will try it tomorrow
 
hi thank you..
but now I'm stuck here...
fysica.PNG
 
You made a mistake in the numerator. After having corrected that mistake, before you use equations (5.1) and (5.2), notice that η is 1 - something, so try to get that 1.
 
Im sorry I tried it but I am again stuck at the next step...
 
Maximilian Popelier said:
Im sorry I tried it but I am again stuck at the next step...
Please show your work.
 
My whole Project or just the formule?
Here is the formule:
fysica.PNG
 

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You made a mistake in the last equality
$$
1 + \frac{-a}{b} = 1 - \frac{a}{b}
$$
$$
1 + \frac{-a}{b} \neq 1 - \frac{a}{-b}
$$
 
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owww... sorry but I am still stuck
fysicca.PNG
 

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How if i do it i have do divise the T1 by the Factor
 
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ficica.PNG

i forgot the 1 -
 
oke and then?
 
Maximilian Popelier said:
oke and then?
Then you should get eq. (5.8). You can write what you got in post #13 such that you get the same term in ##T_1## and ##T_3## in the numerator and the denominator.
 
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sorry i don't get it but i got this
Capture.PNG
 
Maximilian Popelier said:
sorry i don't get it but i got thisView attachment 109348
Compare what is in the parenthesis with the denominator.

I now see you also made a mistake when changing ##T_4## to ##T_3## in the numerator.
 
Nice i got it!
Ty very much
 
Oh i didn't get it i got a "-" wrong i will take a picture
 
$$T_4 = T_3 \left( \frac{p_2}{p_1} \right)^{-\left(1 - \frac{1}{k} \right)}$$ so you should get the right factor in front.
 
Can you please write it all out and take a picture. It will save us a lot of time
 
$$
\begin{align*}
\eta_{\mathrm{th}} &= 1 - \frac{T_4 - T_1}{T_3 - T_2} \\
&= 1 - \frac{T_3 \left( \frac{p_2}{p_1} \right)^{-\left(1 - \frac{1}{k} \right)} - T_1}{T_3 - T_1 \left( \frac{p_2}{p_1} \right)^{\left(1 - \frac{1}{k} \right)}} \\
&= 1 - \left( \frac{p_2}{p_1} \right)^{-\left(1 - \frac{1}{k} \right)} \frac{T_3 - T_1 \left( \frac{p_2}{p_1} \right)^{\left(1 - \frac{1}{k} \right)}}{T_3 - T_1 \left( \frac{p_2}{p_1} \right)^{\left(1 - \frac{1}{k} \right)}}
\end{align*}
$$
 
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Oh but you made a mistake i guess
Im not 100% sure
 
Maximilian Popelier said:
Oh but you made a mistake i guess
Why? I get the same equation as in the book.
 
Hi it isn't very clear for me sorry you hen you replace t4 u use a extra "-" before (1-1/k)
Sorry that i don't get it