- #1
AxiomOfChoice
- 533
- 1
Apparently - that is, if I'm to believe Kolmogorov - we have the following for a bounded linear operator A between two normed spaces:
[tex]
\sup_{\| x \| \leq 1} \|Ax\| = \sup_{\|x\| = 1} \|Ax\|
[/tex]
But why?
[tex]
\sup_{\| x \| \leq 1} \|Ax\| = \sup_{\|x\| = 1} \|Ax\|
[/tex]
But why?