Question about measuring physcial observables

cragar
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So my measurement of a quantum system is an eigenvalue of that operator.
And we are not able to predict what eigenvalue we will get, even if we knew the precise state vector before we make our measurement. But QM allows us to calculate the average of all these eigenvalues, if we made an infinite amount of measurements and then took the average. And we call this the expectation value. So the expectation value that we calculate might not even be a possible eigenvalue that we could measure?
Im just starting to learn QM. Any input will be much appreciated.
 
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cragar said:
So the expectation value that we calculate might not even be a possible eigenvalue that we could measure?

Correct.
 
ok thanks for your answer. Do we just define what physical observables are and then think of ways to measure these quantities that we defined. Or does nature have infinite amount of physical observables.
 
Insights auto threads is broken atm, so I'm manually creating these for new Insight articles. Towards the end of the first lecture for the Qiskit Global Summer School 2025, Foundations of Quantum Mechanics, Olivia Lanes (Global Lead, Content and Education IBM) stated... Source: https://www.physicsforums.com/insights/quantum-entanglement-is-a-kinematic-fact-not-a-dynamical-effect/ by @RUTA
If we release an electron around a positively charged sphere, the initial state of electron is a linear combination of Hydrogen-like states. According to quantum mechanics, evolution of time would not change this initial state because the potential is time independent. However, classically we expect the electron to collide with the sphere. So, it seems that the quantum and classics predict different behaviours!

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