Question about photoelectric effect?

In summary: When one is devising experiments of getting photo electrons from atoms of a particular kind...the atoms are in the form of a 'material' or layer of those atoms called 'Photo active surface/coatings'-the name photo electrons is derived by the mechanism of energy transfer from a photon quantum to a bound electron in the atom of the active material ;so basically its atomic absorption of photons - the work function has to be there as one is not having scattering of photon with a free atom ....the array of atoms are also bound in a structure with surface interaction potentials and the ejected electron has to cross it to be registered as a photo current.Moreover if one looks at Photo electron spectroscopy
  • #1
Clara Chung
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I think that an electron only absorb a photon with energy corresponding to the energy levels in an atom.

If the energy of a photon is higher than the energy between a specific energy level and infinity level (0 eV), it can also absorb the photon and the remained energy is changed to KE.
Am I right?
 
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  • #2
Clara Chung said:
I think that an electron only absorb a photon with energy corresponding to the energy levels in an atom.

If the energy of a photon is higher than the energy between a specific energy level and infinity level (0 eV), it can also absorb the photon and the remained energy is changed to KE.
Let us examin/revisit the event of photo-emission...

The energy of emitted photo electrons is directly proportional to the frequency of incident light.It has also been observed that there must be a minimum energy needed for electrons to

escape from a particular metal surface and is called work function 'W' for that

metal.


The work function can be expressed in terms of frequency as, W= h. frequency(0)

the Photoelectric effect obey the equation,

h.frequency of incident light = k.E. (max) + W
on the above backdrop how you place your argument?
 
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  • #3
drvrm said:
Let us examin/revisit the event of photo-emission...

The energy of emitted photo electrons is directly proportional to the frequency of incident light.It has also been observed that there must be a minimum energy needed for electrons to

escape from a particular metal surface and is called work function 'W' for that

metal.


The work function can be expressed in terms of frequency as, W= h. frequency(0)

the Photoelectric effect obey the equation,

h.frequency of incident light = k.E. (max) + W
on the above backdrop how you place your argument?

Work function is for a metal solid, can't photoelectric effect occur on an atom scale?
 
  • #4
Clara Chung said:
Work function is for a metal solid, can't photoelectric effect occur on an atom scale?

When one is devising experiments of getting photo electrons from atoms of a particular kind...the atoms are in the form of a 'material' or layer of those atoms called 'Photo active surface/coatings'-

the name photo electrons is derived by the mechanism of energy transfer from a photon quantum to a bound electron in the atom of the active material ;
so basically its atomic absorption of photons - the work function has to be there as one is not having scattering of photon with a free atom ....
the array of atoms are also bound in a structure with surface interaction potentials and the ejected electron has to cross it to be registered as a photo current.

Moreover if one looks at Photo electron spectroscopy with variety of photon sources of higher energies
like UV or X-ray sources the spectroscopy helps to unravel the atomic structure.

There may be also "internal conversion" of emitted photons of an atom giving rise to photo electrons called "Auger electrons" but in each case the energy conservation has to be accounted for .
For more details about the the spectroscopy and variety of mechanisms one can look up the wiki or XAS(X-ray photoelectrons ) sites
Such as
<https://en.wikipedia.org/wiki/Photoelectric_effect#Three-step_model> and some more...
 
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Related to Question about photoelectric effect?

1. What is the photoelectric effect?

The photoelectric effect is a phenomenon in which electrons are emitted from a material when it is exposed to light or other electromagnetic radiation. This effect was first observed by Heinrich Hertz in 1887 and was later explained by Albert Einstein in 1905.

2. How does the photoelectric effect work?

The photoelectric effect occurs when photons (particles of light) strike the surface of a material and transfer their energy to electrons. If the energy of the photons is high enough, the electrons can be ejected from the material, creating an electric current. This process is known as the photoelectric effect.

3. What is the significance of the photoelectric effect?

The photoelectric effect is significant because it provided evidence for the particle nature of light and helped to develop the quantum theory. It also led to the development of technologies such as solar panels and photocells, which convert light energy into electrical energy.

4. How is the photoelectric effect related to the work function?

The work function is the minimum amount of energy required to remove an electron from the surface of a material. In the photoelectric effect, the energy of the photons must be equal to or greater than the work function in order for electrons to be ejected from the material.

5. Can the photoelectric effect be explained by classical physics?

No, the photoelectric effect cannot be explained by classical physics. Classical physics predicts that the energy of the ejected electrons would increase with the intensity of the light, but this is not observed in experiments. It was not until the development of quantum theory that the photoelectric effect could be accurately explained.

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