Question about series and sequences

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Homework Statement



I have a function a_{n}=\frac{2+3n}{2n+1}, and I have to find out whether it converges or diverges. I did the ratio test lim_{n\rightarrow\infty}\left|\frac{a_{n+1}}{a_n}\right|. And according to the divergence test, it should diverge. Then it asks if the series, (summation of a_n) converges or diverges.

Now my question is, if a sequence diverges, does the series converge as well?
 
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Why do you say the sequence diverges?

a_{n}=\frac{2+3n}{2n+1} =\frac{3}{2} + \frac{1}{4n+2}

Clearly converges. As to the series, you can see that every term is at least 3/2.
 
The divergence test says that if the limit of a function is not 0, then it diverges. And the limit is 3/2, which is not 0, so it diverges... right?
 
I was under the impression that a function/sequence diverges if the limit is infinite and converges otherwise, though admittedly it's been some time since I had anything to do with this. I'm sure you have a definition in your textbook/lecture notes. Are you sure you're not thinking of the divergence of a series? A series does indeed diverge if the elements don't approach 0.

edit: there is also a possibility that the limit doesn't exit, like with alternating sequences, in which case the sequence diverges also.
 
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There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...

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