Question about series convergence/divergence

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Discussion Overview

The discussion revolves around the convergence and divergence of the harmonic series, specifically addressing the reasoning behind certain substitutions made in the evaluation of partial sums. Participants explore the concept of demonstrating divergence through comparisons with simpler sums.

Discussion Character

  • Technical explanation
  • Conceptual clarification
  • Homework-related

Main Points Raised

  • One participant presents a method for showing that the harmonic series diverges by analyzing partial sums and substituting smaller terms to establish a lower bound.
  • Another participant explains that substituting smaller terms is a strategy to demonstrate that the sum exceeds a particular value, which is essential for proving divergence.
  • A further contribution emphasizes the difficulty of evaluating sums directly and the utility of comparing to simpler sums to show divergence.
  • One participant uses an analogy involving bags of nickels to illustrate the concept of establishing a lower bound through comparison.

Areas of Agreement / Disagreement

Participants generally agree on the approach of using substitutions and comparisons to demonstrate divergence, but there is no explicit consensus on the best methods or the clarity of the original explanation in the textbook.

Contextual Notes

The discussion highlights the challenges in understanding the rationale behind specific mathematical techniques, particularly in the context of series and convergence. There are references to earlier sections of the textbook that may contain relevant information, but these are not elaborated upon.

Who May Find This Useful

Students preparing for calculus exams, particularly those struggling with sequences and series, may find this discussion beneficial for understanding divergence concepts.

grog
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I've always had trouble with sequences and series, and I'm getting ready for upcoming finals now.

There's an example in my calculus text that says:

Show that the harmonic series \sum1/n is divergent.

The solution states: For this particular series it's convenient to consider the partial sums s2,s4,s8,s16,s32,...and show that they become large.

s1=1
s2=1 + (1/2)
s4= 1 + 1/2 + (1/3 + 1/4) > 1+ 1/2 + (1/4 + 1/4) = 1+ 2/2
s8=1 + 1/2 + (1/3 + 1/4) +(1/5 + 1/6 + 1/7 + 1/8) > 1 + 1/2 + (1/4 + 1/4) + (1/8 + 1/8 + 1/8 + 1/8) = 1 +1/2 +1/2 +1/2 = 1+3/2

so the pattern becomes s2n > 1+ n/2
which shows that s2n -> infinity as n -> to infinity and so {sn} is divergent. Therefore the harmonic series diverges.

What I don't understand is why the terms get substituted, for smaller ones (1/3+1/4 becomes 1/4+1/4, etc). If I understood why they were doing that I would understand the rest of it, but there's no explanation in the book, unless it was covered in an earlier section.

Any help understanding would be most appreciated.
 
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Because you want ">". If S= a+ b+ c and I substitute x>a for a, y> b for b, z> c for c, then obviously S< x+ y+ z.
 
Smaller terms are sustituted for simplicity.
The problem with sums is that it is often hard to evaluate a particular sum.
Our goal hear is to show a sum diverges.
It suffices to show the sum excedes any particular value.
We want to show the sum is big, but it is hard to actually find out how big (log(n)).
It is easier to show it is at least as big as a simpler sum.
If we have two sums the one with larger terms will be larger.
By comparing the sum in question to a smaller easier one we have demostrated the sum is a least a big as the simple one.
Say each of us has 100 numbered bags of nickels, and for any particular number your bag has more nickles than mine. We can concluded that you have more nickles total than I without counting either bag. We can also count the nickles in my bags and we have a lower bound on your nickles. In other words if I can afford to to buy a red wagon with my nickels, your will have at least enough to buy the same wagon (assum it offered at the same price).
 
thanks! that's exactly what I was looking for!
 

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