Question about slowdown of the speed of light in solid medium

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Discussion Overview

The discussion revolves around the phenomenon of light slowing down in solid media, particularly focusing on the mechanisms of absorption and re-emission of photons by lattice structures. Participants explore the implications of these processes on the apparent speed of light in materials, touching on concepts such as phonons and electron transitions.

Discussion Character

  • Exploratory
  • Debate/contested
  • Technical explanation

Main Points Raised

  • Some participants suggest that photons are absorbed for a short time by lattice ions and then re-emitted, causing a delay in their travel through the medium.
  • Others argue that the interaction of light with the lattice does not involve individual absorption and re-emission but rather a collective interaction with many molecules simultaneously.
  • A participant questions the validity of the explanation provided in the FAQ, suggesting that it oversimplifies the interaction by not considering the collective behavior of lattice vibrations.
  • There is a discussion about the role of phonons and whether they absorb and re-emit energy, with some participants expressing confusion about the relationship between phonons and the slowing of light.
  • One participant emphasizes the need to understand phonons to grasp the complexities of the topic better.
  • Another participant highlights that the color of objects is determined by the energy levels that electrons can absorb, linking this to the broader discussion of light interaction with materials.

Areas of Agreement / Disagreement

Participants express differing views on the mechanisms of light interaction with solid media, with no consensus reached on the accuracy of the explanations provided in the FAQ. The discussion remains unresolved regarding the specifics of how light slows down in solid materials.

Contextual Notes

Participants note that the wavelength of light is significantly larger than the distance between molecules, which complicates the understanding of individual photon interactions. The discussion also touches on the complexity of phonon behavior and its implications for light propagation.

Who May Find This Useful

This discussion may be of interest to individuals studying optics, solid-state physics, or anyone looking to understand the interaction of light with matter at a fundamental level.

Physicsissuef
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I have read the sticky topic (FAQ of Physics Forums), concretely the topic https://www.physicsforums.com/showpost.php?p=899393&postcount=4" five or six time, and I would ask you about this part:
So the lattice does not absorb this photon and it is re-emitted but with a very slight delay. This, naively, is the origin of the apparent slowdown of the light speed in the material. The emitted photon may encounter other lattice ions as it makes its way through the material and this accumulate the delay.
How it is re-emitted, when it is not first absorbed?
 
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It was absorbed for a short time, is what it is saying. So it is absorbed, just not indefinitely. It is absorbed then re-emitted almost instantly, causing the delay.
 
Physicsissuef said:
I have read the sticky topic (FAQ of Physics Forums), concretely the topic https://www.physicsforums.com/showpost.php?p=899393&postcount=4" five or six time, and I would ask you about this part:

How it is re-emitted, when it is not first absorbed?

Yes, this can be slightly confusing if not understood well; it means that the atoms don't make a transition between different energy levels but that they simply "resonate" according to the em radiation hitting on them and then they re-emits the same em wave (but with a slight delay). Think of a sort of "reflection" of a light beam on a mirror: if the reflection is perfect, the mirror doesn't absorb any energy from the beam, even if the em wave do interact with the mirror's atoms.
"Absorbed" in that contest means exactly this, that is, "energy is not absorbed from the em wave"; it doesn't mean that "there is no interaction"; so "re-emitted" about photons in this case means that they do interact but without energy absorption.
 
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lightarrow said:
Yes, this can be slightly confusing if not understood well; it means that the atoms don't make a transition between different energy levels but that they simply "resonate" according to the em radiation hitting on them and then they re-emits the same em wave (but with a slight delay). Think of a sort of "reflection" of a light beam on a mirror: if the reflection is perfect, the mirror doesn't absorb any energy from the beam, even if the em wave do interact with the mirror's atoms.
"Absorbed" in that contest means exactly this, that is, "energy is not absorbed from the em wave"; it doesn't mean that "there is no interaction".

It was absorbed and released, so why they don't support the theory of electron transitions? Exactly that happens, are they want to say that there is chain reaction (there must be more than 1 atom) to be refraction successful?
 
Physicsissuef said:
It was absorbed and released, so why they don't support the theory of electron transitions? Exactly that happens, are they want to say that there is chain reaction (there must be more than 1 atom) to be refraction successful?
I made the example of reflection, I hoped to be explicative. You could think of sun's light scattering by the air: light interacts with the air's molecules and atoms, but it's not absorbed (its energy is not enough to make them do energy transitions). The prove that it really interacts with air is the blue colour of the sky.
 
lightarrow said:
I made the example of reflection, I hoped to be explicative. You could think of sun's light scattering by the air: light interacts with the air's molecules and atoms, but it's not absorbed (its energy is not enough to make them do energy transitions). The prove that it really interacts with air is the blue colour of the sky.
So if it is not enough to make them do energy transitions, how the light interacts with them?
Can the light just pass through them? But where is the time delay then?
 
Anybody knows?
 
"So the lattice does not absorb this photon and it is re-emitted but with a very slight delay. This, naively, is the origin of the apparent slowdown of the light speed in the material. The emitted photon may encounter other lattice ions as it makes its way through the material and this accumulate the delay."

That explanation is not correct. The wave length of light is about 1000 times the distance between molecules, so a single photon interacts with thousands of molecules at the same time. It does not get absorbed and re-emitted by individual molecules. The treatment in most textbooks, showing the increase in permittivity due to macroscopic polarization, is correct.
 
pam said:
"So the lattice does not absorb this photon and it is re-emitted but with a very slight delay. This, naively, is the origin of the apparent slowdown of the light speed in the material. The emitted photon may encounter other lattice ions as it makes its way through the material and this accumulate the delay."

That explanation is not correct. The wave length of light is about 1000 times the distance between molecules, so a single photon interacts with thousands of molecules at the same time. It does not get absorbed and re-emitted by individual molecules. The treatment in most textbooks, showing the increase in permittivity due to macroscopic polarization, is correct.

The explanation being given, as stated, is the most naive scenario. If you look at the FAQ, there is a clear mention of the phonon modes, which, by definition, is a collective phenomenon. That is what is meant by "lattice ions". It isn't about individual molecules or atoms.

Zz.
 
  • #10
pam said:
"So the lattice does not absorb this photon and it is re-emitted but with a very slight delay. This, naively, is the origin of the apparent slowdown of the light speed in the material. The emitted photon may encounter other lattice ions as it makes its way through the material and this accumulate the delay."

That explanation is not correct. The wave length of light is about 1000 times the distance between molecules, so a single photon interacts with thousands of molecules at the same time. It does not get absorbed and re-emitted by individual molecules. The treatment in most textbooks, showing the increase in permittivity due to macroscopic polarization, is correct.

And how does than the light is slowed down?
 
  • #11
Yeah, he spends most of the article explaining that the conception quoted in the OP is not correct.

Great article ZapperZ. Lattice vibrations are quantized? ❊brain explodes❊ This site is so great.

pam said:
The wave length of light is about 1000 times the distance between molecules, so a single photon interacts with thousands of molecules at the same time.

Is there something physical, or some area of effect, that's physically the same size as the wavelength?
 
  • #12
CaptainQuasar said:
Yeah, he spends most of the article explaining that the conception quoted in the OP is not correct.

Great article ZapperZ. Lattice vibrations are quantized? ❊brain explodes❊ This site is so great.



Is there something physical, or some area of effect, that's physically the same size as the wavelength?


What about my question?
 
  • #13
Physicsissuef said:
What about my question?

I'm not a physicist myself but it seems to me that you'd need to achieve some understanding of phonons to better comprehend ZapperZ's article.
 
  • #14
ZapperZ can you tell me concretely what happens? Are the phonons (the lattice of ions) absorbing and then re-emiting the energy?
 
  • #15
If the electrons absorb the energy of any portion of the visible spectrum, the light that transmits through will appeared colored according to the portion of the spectrum absorbed. In fact, the color of any object is a direct result of what levels of energy the electrons in the substance will absorb!
So what actually happens here?
 
  • #16
Just from my own point of view not understanding this myself, it may more successfully encourage people to answer you if you ask questions that demonstrate that you're making a serious attempt to understand what phonons are and how they fit into this topic.

(Or, it might just be something that can't be boiled down to as simple a form as you want it to be.)
 
  • #17
I think it is not so much complicated. Just so much information confuses you.
I found http://science.howstuffworks.com/light12.htm" first saying that:
The light wave penetrates deeply into the material, and causes small vibrations in the electrons. The electrons pass these vibrations on to the atoms in the material, and they send out light waves of the same frequency as the incoming wave. But this all takes time. The part of the wave inside the material slows down, while the part of the wave outside the object maintains its original frequency.
I found http://science.howstuffworks.com/question404.htm" on the same site:
Most of the time, it is a combination of the above that happens to the light that hits an object. The electrons in different materials vary in the range of energy that they can absorb. A lot of glass, for example, blocks out ultraviolet (UV) light. What happens is the electrons in the glass absorb the energy of the photons in the UV range while ignoring the weaker energy of photons in the visible light spectrum. If the electrons absorb the energy of any portion of the visible spectrum, the light that transmits through will appeared colored according to the portion of the spectrum absorbed. In fact, the color of any object is a direct result of what levels of energy the electrons in the substance will absorb!
Again, the http://science.howstuffworks.com/light10.htm":
The atoms in some materials hold on to their electrons loosely. In other words, the materials contain many free electrons that can jump readily from one atom to another within the material. When the electrons in this type of material absorb energy from an incoming light wave, they do not pass that energy on to other atoms. The energized electrons merely vibrate and then send the energy back out of the object as a light wave with the same frequency as the incoming wave. The overall effect is that the light wave does not penetrate deeply into the material.

So what is actually correct??
 
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  • #18
Physicsissuef said:
I think it is not so much complicated. Just so much information confuses you.


I found http://science.howstuffworks.com/question404.htm" on the same site:
Most of the time, it is a combination of the above that happens to the light that hits an object. The electrons in different materials vary in the range of energy that they can absorb. A lot of glass, for example, blocks out ultraviolet (UV) light. What happens is the electrons in the glass absorb the energy of the photons in the UV range while ignoring the weaker energy of photons in the visible light spectrum. If the electrons absorb the energy of any portion of the visible spectrum, the light that transmits through will appeared colored according to the portion of the spectrum absorbed. In fact, the color of any object is a direct result of what levels of energy the electrons in the substance will absorb!

Again, the http://science.howstuffworks.com/light10.htm":
The atoms in some materials hold on to their electrons loosely. In other words, the materials contain many free electrons that can jump readily from one atom to another within the material. When the electrons in this type of material absorb energy from an incoming light wave, they do not pass that energy on to other atoms. The energized electrons merely vibrate and then send the energy back out of the object as a light wave with the same frequency as the incoming wave. The overall effect is that the light wave does not penetrate deeply into the material.


So what is actually correct??

The first refers to transparent materials (like glass), the second to conductors (like metals).
 
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  • #19
Actually all are for one same thing. On the third link, just below the quoted text, see there is Law of Reflection. Does anybody know what is correct?
 
  • #20
Physicsissuef said:
And how does than the light is slowed down?
Probably it's thinking about photons that confuses you, so you could prefer not to think about photons at all, since Maxwell's equations are enough to treat the phenomenon. The light's velocity we are talking here is what it's called "phase velocity" of a wave. When an em wave interacts with atoms without being absorbed, the atom or the atoms collectively (as in the case of glass) oscillate in response of that wave, so generating another, second, wave which is not in phase with the first one, but with a slight phase delay; this then will make the near subsequent atoms oscillate which then will emit another, third wave, with a slight phase delay with respect to the second and so you have a phase delay proportional to the light path inside the material. Now remember that we are talking about "phase velocity" and you understand (I hope! :smile:) why light's speed is slowed down inside the glass.
A link about waves animations:
http://www.kettering.edu/~drussell/demos.html
 
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  • #21
lightarrow said:
Probably it's thinking about photons that confuses you, so you could prefer not to think about photons at all, since Maxwell's equations are enough to treat the phenomenon. The light's velocity we are talking here is what it's called "phase velocity" of a wave. When an em wave interacts with atoms without being absorbed, the atom or the atoms collectively (as in the case of glass) oscillate in response of that wave, so generating another, second, wave which is not in phase with the first one, but with a slight phase delay; this then will make the near subsequent atoms oscillate which then will emit another, third wave, with a slight phase delay with respect to the second and so you have a phase delay proportional to the light path inside the material. Now remember that we are talking about "phase velocity" and you understand (I hope! :smile:) why light's speed is slowed down inside the glass.
A link about waves animations:
http://www.kettering.edu/~drussell/demos.html
They are some kind of excited?
 
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  • #22
Physicsissuef said:
They are some kind of excited?
A kind, yes, because the term excitation is usually used for energy transitions (but you have to ask someone else about this ).
 
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  • #23
lightarrow said:
A kind, yes, because the term excitation is usually used for energy transitions (but you have to ask someone else about this ).

But if the energy is not enough strong to make them oscillate, what happens?
 
  • #24
Physicsissuef said:
But if the energy is not enough strong to make them oscillate, what happens?
In this case you can forget energy: there is no energy absorption, no energy transitions; they oscillate without the need of any energy.
Edit: quantum world is not the same as classical world. :smile:
 
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  • #25
Physicsissuef said:
Actually all are for one same thing. On the third link, just below the quoted text, see there is Law of Reflection. Does anybody know what is correct?
With "the first" and "the second" I intended the articles quoted in my post, so they are "the second" and "the third" of your previous post.
 
  • #26
lightarrow said:
In this case you can forget energy: there is no energy absorption, no energy transitions; they oscillate without the need of any energy.
So they oscillate in presence of electromagnetic wave, right?
 
  • #27
Physicsissuef said:
So they oscillate in presence of electromagnetic wave, right?
Yes.
 
  • #28
And what do you think, is this http://science.howstuffworks.com/light10.htm"?
The atoms in some materials hold on to their electrons loosely. In other words, the materials contain many free electrons that can jump readily from one atom to another within the material. When the electrons in this type of material absorb energy from an incoming light wave, they do not pass that energy on to other atoms. The energized electrons merely vibrate and then send the energy back out of the object as a light wave with the same frequency as the incoming wave. The overall effect is that the light wave does not penetrate deeply into the material.
 
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  • #29
lightarrow said:
Yes, this can be slightly confusing if not understood well; it means that the atoms don't make a transition between different energy levels but that they simply "resonate" according to the em radiation hitting on them and then they re-emits the same em wave (but with a slight delay). Think of a sort of "reflection" of a light beam on a mirror: if the reflection is perfect, the mirror doesn't absorb any energy from the beam, even if the em wave do interact with the mirror's atoms.
"Absorbed" in that contest means exactly this, that is, "energy is not absorbed from the em wave"; it doesn't mean that "there is no interaction"; so "re-emitted" about photons in this case means that they do interact but without energy absorption.

So what happens to the original photon after the interaction ?
 
  • #30
Physicsissuef said:
And what do you think, is this http://science.howstuffworks.com/light10.htm"?
No. The article means to talk about a perfect reflection (no energy absorption at all), so it's confusing to say "When the electrons in this type of material absorb energy from an incoming light wave".
 
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