Question about system stability

  • Thread starter Thread starter Drao92
  • Start date Start date
  • Tags Tags
    Stability System
Drao92
Messages
70
Reaction score
0
If a system transfer function has a pole equal with 1 , j, cos(pi/4)+j*sin(pi/4) in other words its location is on the margin of the unit circle, it`s the system stable? In my opinion it`s not stable because we have a sum of 1 which doesn't converge but I am not sure. Everywhere I've read it says the poles must be inside the unit circle but it doesn't say anything about poles on the margin of the unit circle. Can somebody give me a precise answer? Thanks!
Edit: I am referring to z-plane
 
Physics news on Phys.org
Drao92 said:
If a system transfer function has a pole equal with 1 , j, cos(pi/4)+j*sin(pi/4)
What does this (above) mean?
Drao92 said:
in other words its location is on the margin of the unit circle, it`s the system stable? In my opinion it`s not stable because we have a sum of 1 which doesn't converge but I am not sure. Everywhere I've read it says the poles must be inside the unit circle but it doesn't say anything about poles on the margin of the unit circle. Can somebody give me a precise answer? Thanks!
Edit: I am referring to z-plane
What's the z-plane? Do you mean the plane z = 0?
 
Iam talking about z transform and stability analysis.
Like if H(z)=z/(z-1), pole is 1. is it stable?
I have exam in 5 hours and i need an answer .
 
Last edited:
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
Back
Top