Question about terminal velocity

AI Thread Summary
To find the terminal velocity of an object falling under the influence of gravity and a drag force, the equation W = bv^2 is used, where W is the weight, b is the drag coefficient, and v is the velocity. In this case, with W = 4 N and b = 3 N∙s²/m, the calculated terminal velocity is approximately 1.15 m/s. At terminal velocity, the drag force equals the weight, resulting in zero net force and no further acceleration. This understanding aligns with Newton's second law, confirming the method of equating the forces is correct. The discussion emphasizes the importance of grasping the underlying principles behind the calculations.
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Homework Statement



An object of weight W falls from rest subject to a frictional drag force bv^2. What maximum ("terminal") velocity will it approach if W = 4 N and b = 3 N∙ s2/m?





The Attempt at a Solution



I set W = Bv^2 and solved for v and got 1.15. I am not quite sure if this was the method of doing this. Some insight would be nice.
 
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Yeah, at the point where the drag force equals the weight, the net force on the object will be zero, meaning that it will no longer accelerate (by Newton's second law). Hence, it continues to fall at a constant velocity, the terminal velocity.

That's why equating the two forces is the method used to solve the problem.
 
Thank you, sometimes I am able to solve problems, but can't explain why!
 
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