Question about the Conservation of Energy

AI Thread Summary
The discussion centers on the application of the conservation of energy to determine the velocity of a cart rolling down a ramp and flying off a table. The user correctly uses the equation mgh1 = mgh2 + 1/2mv2 but struggles with the height values, initially using h1 as 5 meters and h2 as 3 meters. Clarification is provided that the total height should be considered from the ground level, suggesting h1 should be 8 meters if the table is at 3 meters. The user questions whether the release height can be treated as "0" height, indicating a misunderstanding of reference points in energy calculations. The conversation emphasizes the importance of correctly defining height in energy conservation equations.
nicholz
Messages
2
Reaction score
0
If a cart rolled down a ramp 5 meters high and flew off a a table at 3 meters high, what would its velocity be?

please let me know where i go wrong, i was using the law of conservation of energy

mgh1=mgh2+1/2mv2
mg(h1-h2)=1/2mv2
v=square root of 2g(h1-h2)

where h1=5 and h2=3

i plugged in numbers for the variables and i can't seem to get it to work out. is the equation i came up with correct?
edit: i was thinking that it should come out to the square root of 2gh. would that be right though? can i consider the release height to be the "0" height here?
 
Last edited:
Physics news on Phys.org
Yes your equation is correct, though since the ramp is 5m high and then the table is 3m high, shouldn't h1=8m?
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top