Question about unique real number

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The discussion revolves around proving that if a + b = a + c, then b = c, and how this relates to the uniqueness of the number zero. The user initially finds the proof straightforward using axioms of identity and associativity. They express confusion about why the book states that this also proves the uniqueness of zero. A clarification is provided that if two numbers both satisfy the identity property of zero, they must be equal, thus demonstrating that there is only one real number that can be denoted as zero. The user concludes that their understanding has improved after the discussion.
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hello guys I am new in this forum
i start to self learn calculus tom apostol (in my college we got another book)
i start from the very beginning of the chapter. so this not really a homework. if i post thread in wrong sub-forum please remind me :)

Homework Statement



prove : If a+b = a+c, then b = c.

Homework Equations



this also prove zero number is unique.

The Attempt at a Solution



the prove was easy

using AXIOM EXISTENCE OF IDENTITY ELEMENTS & ASSOCIATIVE

there is a number y such that y + a = O
then
y+(a+b) = y+(a+c)

(y+a)+b=(y+a)+c

0+b=0+c

b=c

but why in the book say this also prove number 0 is unique? in other words only one real number have the property zero?!

thank u :)
 
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How did you define the zero number?
 
R136a1 said:
How did you define the zero number?

axiom says : there exist real number denote by 0, such that for every real x, we have x+0=x

see the underlined, it doesn't say : there exist ONE real number.
so we have to prove only exactly one real number denote by 0. but i still don't get it how to prove this.. :)
 
Can you see how to use the result you have just proved:

a + b = a + c => b = c

To prove that there is only one 0?
 
Assume there are two real numbers 0 and 0'. Both satisfy x+0 = x and x+0' = 0' for all x. Can you deduce 0 = 0'?
 
ok guys thanks for the help..
i don't have problem anymore.. its clear now
 
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