Question on Archimedes principle.

AI Thread Summary
The discussion revolves around calculating the tension in a string holding a solid sphere in an upward-accelerating tank and determining the sphere's acceleration if the string breaks. The sphere has a mass of 2 kg and a specific gravity of 0.5, leading to a buoyant force that needs to be adjusted for the tank's acceleration. Participants emphasize using an accelerating frame of reference, noting that the effective gravitational force increases due to the upward acceleration. The correct buoyant force calculation incorporates both gravitational and acceleration effects, leading to a revised understanding of the problem. The conversation highlights the importance of accurately applying Archimedes' principle in non-inertial frames.
vkash
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Homework Statement



A solid sphere of mass m=2 kilogram and specific gravity s=0.5 is held stationary to a tank as shown in figure. The tank is accelerating upward with a=2ms-2. calculate the tension in the string? If suddenly string break then the acceleration of the ball in frame of tank.

Homework Equations



Archimedes principle

The Attempt at a Solution


see in attachment.
for second question. My answer is
net force =B-mg=20 so acceleration in frame of ground is 10. In frame it should 10-2=8.
 

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vkash said:

Homework Statement



A solid sphere of mass m=2 kilogram and specific gravity s=0.5 is held stationary to a tank as shown in figure. The tank is accelerating upward with a=2ms-2. calculate the tension in the string.

Homework Equations



Archimedes principle

The Attempt at a Solution


see in attachment.

Hi Vkash,
What is your question?

ehild
 
ehild said:
Hi Vkash,
What is your question?

ehild
A solid sphere of mass m=2 kilogram and specific gravity s=0.5 is held stationary to a tank as shown in figure. The tank is accelerating upward with a=2ms-2.
(1) calculate the tension in the string?
(2) If suddenly string break then the acceleration of the ball in frame of tank?
I have tried to answer these questions. Where am i wrong.
 
The problem is easiest to solve if you use the accelerating frame of reference, fixed to the tank. Have you learned about accelerating frames of reference? You feel heavier in a lift which accelerates upward as if the gravitational acceleration g would be bigger. And you feel lighter in a frame of reference accelerating downward. In a falling lift you are weightless.

Buoyant force arises because of the weight of the liquid. In a falling tank, there would be no buoyant force. You could immerse any object into the liquid, it would stay at the same place.
This tank accelerates upward with a=2 m/s^2. Everything feels heavier, as if the gravitational constant would be g'=g+2 instead of 10 m/s^2. Even the buoyant force will be larger than in the tank in rest.

Can you proceed?


ehild
 
ehild said:
The problem is easiest to solve if you use the accelerating frame of reference, fixed to the tank. Have you learned about accelerating frames of reference? You feel heavier in a lift which accelerates upward as if the gravitational acceleration g would be bigger. And you feel lighter in a frame of reference accelerating downward. In a falling lift you are weightless.

Buoyant force arises because of the weight of the liquid. In a falling tank, there would be no buoyant force. You could immerse any object into the liquid, it would stay at the same place.
This tank accelerates upward with a=2 m/s^2. Everything feels heavier, as if the gravitational constant would be g'=g+2 instead of 10 m/s^2. Even the buoyant force will be larger than in the tank in rest.

Can you proceed?


ehild

yes i have read this in starting mechanics.(working with non inertial frame of reference)
In your way.
B=M(g+a)+T
Is it correct?

if string is snapped.
B-m(g+a)=ma'
answer of second question.
 
I hope It will be OK if you calculate the buoyant force correctly.

ehild
 
ehild said:
I hope It will be OK if you calculate the buoyant force correctly.

ehild

volume of ball is 2/500=4*10-3
B=(4*10-3)*(10)*(1000)
here i did it wrong.
It should B=(4*10-3)*(10+2)*(1000)
thanks ehild. I got the mistake.
 
Well done!

ehild
 
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