Question on deformations of members under axial loading

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The discussion revolves around calculating the deformation of a 250-mm aluminum tube and a solid brass rod under axial loading. The user has successfully calculated the elongations of both components, finding them to be equal at 0.1325 mm, leading to a total deformation of 3.75E-4 mm based on the screw's rotation. There is confusion regarding why the total deformation is not the difference between the tube's tension and the rod's compression, as initially assumed. The professor clarifies that the deformations add up rather than cancel out, which is a key point in understanding the system's behavior under load. The user seeks further clarification on the final lengths of the tube and rod after deformation.
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Homework Statement


N/A

A 250-mm long aluminum tube of 36mm outer diameter and 28mm inner diameter may be closed at both ends by means of single threaded screw on covers of 1.5mm pitch. With one cover screwed on tight, a solid brass rod of 25mm diameter is placed inside the tube and the second cover is screwed on. Since the rod is slightly longer than the tube it is observed that the cover must be forced against the rod by rotating it one-quarter turn before it can be tightly closed. Determine the deformation of the rod and of the tube.

Homework Equations

I have no problem calculating the elongations of each part, but wonder in the end why they add up to 3.75E-4 (the total deformation of the system as found from the threaded screw) when I thought the outer tube is in tension and the inner rod is in compression. Wouldn't this mean the total deformation of the system would be the difference between the two values? Our professor says no, but I am confused as to why.

Any help is appreciated/if you have more info as to the solution let me know.

The Attempt at a Solution



With other given values I calculated delta rod=0.1325mm and delta tube=0.1325, which adds up to delta total=3.75E-4 (found by multiplying .25 turn* the pitch of 1.5mm)
 
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Can you explain your statement: "delta rod=0.1325mm and delta tube=0.1325, which adds up to delta total=3.75E-4"? The final length of both the tube and the rod is 250.1325 mm? Or not?
 

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