Questions about understanding circular motion & the forces involved

AI Thread Summary
Understanding circular motion involves recognizing the distinction between centripetal and centrifugal forces. When on a spinning turntable, inertia causes a tendency to move straight until a barrier redirects the path into a circle. Centrifugal force is perceived in a rotating frame but is not a true force; it results from inertia and the centripetal force acting inward. The sensation of "extra weight" during acceleration, such as in a car, is due to the normal force acting against inertia, creating a perceived gravitational effect. Ultimately, the forces felt are real interactions within the body, while inertial forces are artifacts of the chosen frame of reference.
Sho Kano
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Hey, I'm having some difficulty in understanding circular motion and it's forces. Here is the situation I'm on:
Imagine you are on a smooth turn-table with smooth shoes and the table starts spinning. Because of inertia, and because the frictional force is not nearly enough to keep you going in a circle, you'll start moving in a more/less straight line towards the rim of the table. Now let's say the table had a fence along the rim, and you eventually bump into the fence and you're forced to move in a circular path.

Is the perceived gravity the same as the centrifugal force in this case? Do you experience a centrifugal force in situation (a) where you didn't hit the fence yet and (b) at the fence?

My understanding is that the centrifugal force is purely you're tendency to move tangentially. So since there is no or little resistance to that in situation (a), you don't experience anything. In (b) however, you will experience a force radially outward (??) - Why?

It seems like centrifugal forces are similar to the backward force that you experience when you accelerate inside a car.
 
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Sho Kano said:
Hey, I'm having some difficulty in understanding circular motion and it's forces. Here is the situation I'm on:
Imagine you are on a smooth turn-table with smooth shoes and the table starts spinning. Because of inertia, and because the frictional force is not nearly enough to keep you going in a circle, you'll start moving in a more/less straight line towards the rim of the table. Now let's say the table had a fence along the rim, and you eventually bump into the fence and you're forced to move in a circular path.

Is the perceived gravity the same as the centrifugal force in this case? Do you experience a centrifugal force in situation (a) where you didn't hit the fence yet and (b) at the fence?
To apply Newton's laws, you have to examine the motion in a non-rotating frame of reference. If there was no force acting on the body, it would fly off in a straight line in the tangential direction (Newton's first law). So there has to be a force that keeps deflecting it toward the centre of rotation. The change in velocity is inward. So there is an inward force. It is not centrifugal (away from the centre). Rather it is centripetal (toward the centre).
My understanding is that the centrifugal force is purely you're tendency to move tangentially. So since there is no or little resistance to that in situation (a), you don't experience anything. In (b) however, you will experience a force radially outward (??) - Why?
There is no force required to move in a straight line at constant speed. The tangential speed does not change. The direction changes - always changing to deflect the motion toward the centre of rotation.

Centrifugal force is a force sensation that appears in a rotating frame of reference. It is not a Newtonian force. If you analyse the forces from an inertial, non-rotating, frame of reference, there is only an inward force.

AM
 
Sho Kano said:
It seems like centrifugal forces are similar to the backward force that you experience when you accelerate inside a car.
Yes, these are "inertial forces", which are introduced solely to make Newton's 2nd Law work in non-inertial (accelerated) frames, and account for the object's coordinate acceleration in these frames. Inertial forces don't obey Newton's 3rd Law, and you don't "experience" them as you experience interaction forces.

Sho Kano said:
Do you experience a centrifugal force in situation (a) where you didn't hit the fence yet and (b) at the fence?
Depends on what you mean by "experience". To calculate the acceleration by Newtons 2nd Law in the rotating frame you always include the inertial centrifugal force, and eventually the inertial Coriolis force.
 
Okay, so these inertial forces do not really exist, but what accounts for the "extra weight" I feel while being accelerated?

What I understand is: In the situation of in an accelerating car, if I put a scale between the seat and my back, a non-zero number would pop up. This is analogous to just standing on a scale right? You would have a "gravity" towards the seat. And this perceived gravity is just the normal force accelerating you. So in short, you'll always perceive gravity in the opposite direction of the net force on you?

In the case of the turn-table, what I feel at the fence is the centripetal force pushing inward. What I perceive, is a apparent gravity/compression due to that force acting on my back (?)
 
Sho Kano said:
So in short, you'll always perceive gravity in the opposite direction of the net force on you?
Yes, you "feel" weight opposite to your proper acceleration (what an accelerometer measures), due to "real" interaction forces. Inertial forces do not cause proper acceleration, so you don't "feel" them.
 
Sho Kano said:
Okay, so these inertial forces do not really exist, but what accounts for the "extra weight" I feel while being accelerated?
The centrifugal "force" phenomenon really exists (so long as the force providing the centripetal acceleration is not gravity)! It is just that it is not a Newtonian force. If you are being swung around on a rope tied to a pole, the rope is constantly accelerating you toward the centre and you feel that pull. However, your tangential motion keeps the distance between you and the centre of rotation from decreasing. So in your frame of reference (the non-inertial, rotating and, therefore, accelerating, frame) looking just at the rope and pole, you do not sense that your motion is changing. Yet you feel a force (a tension within your body that seems to be trying to send you outward). The reason you feel any force at all is because of the mechanical nature of the applied centripetal force. The rope may be tied to your belt, which in turn applies mechanical tensions to your waist which, through inter-cellular bonds of your body's bones and tissues, creates tensions between all the cells in your body. It is that tension within your body, caused by your inertia, that you perceive as centrifugal force.

What I understand is: In the situation of in an accelerating car, if I put a scale between the seat and my back, a non-zero number would pop up. This is analogous to just standing on a scale right?
When you are accelerated forward in a car when you step on the gas you feel that something is pushing you rearward. But, when correctly analysed from an inertial frame of reference, there is only one force on you and it is the force from the seat pushing you forward. The rearward force that you exert on the seat is not caused by something pushing you into the seat. Rather it is your inertia resisting the forward push from the seat.

You would have a "gravity" towards the seat. And this perceived gravity is just the normal force accelerating you. So in short, you'll always perceive gravity in the opposite direction of the net force on you?

In the case of the turn-table, what I feel at the fence is the centripetal force pushing inward. What I perceive, is a apparent gravity/compression due to that force acting on my back (?)
Gravity is different than all other forces. There is no "inertial force effect" when the acceleration is provided by gravity. When an astronaut orbits the Earth he/she feels no centrifugal (outward) effect - no sensation of centrifugal force. This is because the force acts directly on each atom rather then through tensions within your body. Similarly, your body will not push against a spring scale because the scale is accelerating at the same rate as you are. It is only if there is a perceptible difference between the gravitational forces from one end of your body to the other that you will feel any tension within your body.

AM
 
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Andrew Mason said:
There is no "inertial force effect" when the acceleration is provided by gravity.
The acceleration by gravity is locally indistinguishable from an "inertial force effect".

Andrew Mason said:
When an astronaut orbits the Earth he/she feels no centrifugal (outward) effect - no sensation of centrifugal force.
You never feel the inertial centrifugal force, or any other inertial force.
 
Thanks guys I think I got it now. What accounts for what you feel are the forces within your body. In an accelerating car the seat pushes your back; because your chest is not initially accelerating, there will be somewhat of a compression in your body.
Andrew Mason said:
If you are being swung around on a rope tied to a pole, the rope is constantly accelerating you toward the centre and you feel that pull. However, your tangential motion keeps the distance between you and the centre of rotation from decreasing. So in your frame of reference (the non-inertial, rotating and, therefore, accelerating, frame) looking just at the rope and pole, you do not sense that your motion is changing. Yet you feel a force (a tension within your body that seems to be trying to send you outward).
In this situation, there is actually tension instead of compression. If we replace the guy with a spring, the tension from the rope extends the top part, but the other part is left swinging around. And so a shoe would have an apparent force on it so when it flies off, it goes tangentially by virtue of inertia.

So to sum up, the apparent force or inertial force is of direct result from the real (applied) force, and it is because of inertia that any of this happens. You don't actually feel inertia.
 
Sho Kano said:
inertial force is of direct result from the real (applied) force
Not really. Inertial forces are an artifact of the coordinate choice. In the inertial frame there is only the real force, but no inertial force.
 
  • #10
A.T. said:
The acceleration by gravity is locally indistinguishable from an "inertial force effect".

You never feel the inertial centrifugal force, or any other inertial force.
I am not sure what you mean by these terms. What would you say that astronauts experience when whirling around in the centrifuge with their face feeling like it is being squished into their brains?

My point is that there is a huge difference between being whirled around in a centrifuge and being whirled around the Earth in orbit. There is a similar perceptible and a real physical difference between gravitational free-fall and an accelerating rocket or car.

AM
 
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  • #11
Sho Kano said:
So to sum up, the apparent force or inertial force is of direct result from the real (applied) force, and it is because of inertia that any of this happens. You don't actually feel inertia.
A dog tied to a 100lb cannon ball by a neck chain will experience the effect of inertia when he sees his first squirrel.

AM
 
  • #12
A.T. said:
Not really. Inertial forces are an artifact of the coordinate choice. In the inertial frame there is only the real force, but no inertial force.
Sure the inertial force only exists in a non-inertial frame; I meant that what you feel is due to the real force pushing on you.
Andrew Mason said:
A dog tied to a 100lb cannon ball by a neck chain will experience the effect of inertia when he sees his first squirrel.
Do you mean in a way that it can't move? But you can't actually "feel" inertia right? In this case the dog feels a tension force acting opposite to it's motion- which is an effect of inertia (?)
 
  • #13
Sho Kano said:
Sure the inertial force only exists in a non-inertial frame; I meant that what you feel is due to the real force pushing on you.

Do you mean in a way that it can't move? But you can't actually "feel" inertia right? In this case the dog feels a tension force acting opposite to it's motion- which is an effect of inertia (?)
The effects are felt regardless of which frame you are doing the analysis in. If you are experiencing it but analysing it (ie. by applying Newton's laws) in an inertial frame, you conclude that there is only the Newtonian force acting on you and what you feel is the effect of your own inertia. If you are experiencing it and analysing it your non-inertial frame (ie. you assume that you are not accelerating) you will conclude that there must be a force is being applied in the opposite direction (ie. opposite to which the actual Newtonian force is being applied).

AM
 
  • #14
Andrew Mason said:
The effects are felt regardless of which frame you are doing the analysis in. If you are experiencing it but analysing it (ie. by applying Newton's laws) in an inertial frame, you conclude that there is only the Newtonian force acting on you and what you feel is the effect of your own inertia. If you are experiencing it and analysing it your non-inertial frame (ie. you assume that you are not accelerating) you will conclude that there must be a force is being applied in the opposite direction (ie. opposite to which the actual Newtonian force is being applied).

AM
Right, in an inertial frame there must be only a Newtonian force acting on me, so what I feel is explained by inertia. In an non-inertial frame however, all I know is that I feel a force in the opposite direction- and that is explained by the inertial force. In both situations though, what I feel is the same sensation, and that can be explained by the compression/stretching the earlier posts. Is this right?
 
  • #15
Sho Kano said:
Right, in an inertial frame there must be only a Newtonian force acting on me, so what I feel is explained by inertia. In an non-inertial frame however, all I know is that I feel a force in the opposite direction- and that is explained by the inertial force. In both situations though, what I feel is the same sensation, and that can be explained by the compression/stretching the earlier posts. Is this right?
Basically, that's right. In the case of you rotating about a central point, there is only the Newtonian centripetal force acting on you. The force that seems to be counteracting the centripetal force (when applying Newton's laws in your rotating frame treated as if it were an inertial frame), is sometimes referred to as an inertial force but that just confuses everyone. It is an inertial effect. No force is needed to keep you out there.

AM
 
  • #16
Sho Kano said:
Sure the inertial force only exists in a non-inertial frame; I meant that what you feel is due to the real force pushing on you.
Yes. Your coordinate acceleration (dv/dt) is frame dependent, and so are inertial forces. What you "feel" is frame independent, and so are the real forces.
 
  • #17
Andrew Mason said:
I am not sure what you mean by these terms. What would you say that astronauts experience when whirling around in the centrifuge with their face feeling like it is being squished into their brains?
They experience deformations due to the non-uniformly applied real centripetal force. This is a frame independent effect, while inertial forces are frame dependent.

Andrew Mason said:
My point is that there is a huge difference between being whirled around in a centrifuge and being whirled around the Earth in orbit.
Yes, because here (in Newtonian terms) the centripetal force is applied approximately uniformly to a small body, so it doesn't cause much deformation.
 
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  • #18
A.T. said:
The acceleration by gravity is locally indistinguishable from an "inertial force effect".

You never feel the inertial centrifugal force, or any other inertial force.
Perhaps it is a matter of terminology. I use the term "inertial force effect" or "inertial effect" to refer to the perceived force (perceived by application of Newton's laws in the non-inertial frame of reference). Inside a non-rotating free falling or orbiting space-craft, there would be no perceived forces. But inside that same space-craft being hurled around in a centrifuge, forces would be perceived (by application of Newton's laws in the space-craft frame). So, in that sense, I would say that gravity is distinguishable from an "inertia force effect" - in the sense that there is no local inertial force effect in the non-inertial frame if the only real forces are gravitational.

AM
 
  • #19
Andrew Mason said:
Perhaps it is a matter of terminology.
Yes, as usual you prefer a non-standard one.

Andrew Mason said:
Inside a non-rotating free falling or orbiting space-craft, there would be no perceived forces
Inertial forces have nothing to do with inside or outside. They depend on the chosen reference frame, which extends to infinity, and includes the inside and outside of the space-craft.
 
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  • #20
A.T. said:
Yes, as usual you prefer a non-standard one.Inertial forces have nothing to do with inside or outside. They depend on the chosen reference frame, which extends to infinity, and includes the inside and outside of the space-craft.
Ok. We are in agreement on that. But what is it that leads the observer in the reference frame of the free-falling or orbiting spacecraft to posit an outward force acting on the space-craft and its contents?

AM
 
  • #21
Andrew Mason said:
Ok. We are in agreement on that. But what is it that leads the observer in the reference frame of the free-falling or orbiting spacecraft to posit an outward force acting on the space-craft and its contents?
If he is using Newtonian physics a free falling frame under gravity is non-inertial. In GR a free falling frame is inertial and there are no inertial forces acting.
 
  • #22
A.T. said:
If he is using Newtonian physics a free falling frame under gravity is non-inertial. In GR a free falling frame is inertial and there are no inertial forces acting.
I was trying to understand your statement: the acceleration by gravity is locally indistinguishable from an "inertial force effect". Did you mean to say "the frame of reference of a body undergoing acceleration by gravity is locally indistinguishable from an inertial reference frame"? I don't see inertial forces arising in such a frame.

AM
 
  • #23
Andrew Mason said:
I don't see inertial forces arising in such a frame.
That's the GR interpretation.
 
  • #24
A.T. said:
That's the GR interpretation.
It is also the conclusion one reaches by applying Newton's laws of motion in the non-inertial, falling reference frame.

AM
 
  • #25
Andrew Mason said:
It is also the conclusion one reaches by applying Newton's laws of motion in the non-inertial, falling reference frame.
No, it isn't. If the frame is non-inertial, then there are inertial forces.
 
  • #26
A.T. said:
No, it isn't. If the frame is non-inertial, then there are inertial forces.
Perhaps you could elaborate. I don't see the inertial forces in the non-inertial frame of reference of a free-falling or orbiting space-craft.

AM
 
  • #27
Andrew Mason said:
I don't see the inertial forces in the non-inertial frame of reference
You can't see forces in general. Inertial forces are introduced to make Newtons 2nd Law work in non-inertial frames. This was explained in post #3 already.
 
  • #28
A.T. said:
You can't see forces in general. Inertial forces are introduced to make Newtons 2nd Law work in non-inertial frames. This was explained in post #3 already.
??. But that is my point. One does not need to introduce inertial forces in order to make Newton's laws work in a non-inertial frame where the acceleration is caused by gravity.

AM
 
  • #29
Andrew Mason said:
Perhaps you could elaborate. I don't see the inertial forces in the non-inertial frame of reference of a free-falling or orbiting space-craft.
The space-craft is at rest in this frame, yes? In the Newtonian model, gravity is a real force in this frame, yes? The inertial force is the one holding the space-craft in place against the real force of gravity.

Edit: of course, we could adopt the GR model and consider that gravity is not a real force. But then the frame is inertial which goes against the claim that the frame is non-inertial.
 
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  • #30
Andrew Mason said:
One does not need to introduce inertial forces in order to make Newton's laws work in a non-inertial frame where the acceleration is caused by gravity.
Assuming Newton's model of Gravity (real frame independent interaction force), you have to introduce an inertial force to make Newton's 2nd Law work in a free falling frame.
 
  • #31
jbriggs444 said:
The space-craft is at rest in this frame, yes? In the Newtonian model, gravity is a real force in this frame, yes? The inertial force is the one holding the space-craft in place against the real force of gravity.

Edit: of course, we could adopt the GR model and consider that gravity is not a real force. But then the frame is inertial which goes against the claim that the frame is non-inertial.

A.T. said:
Assuming Newton's model of Gravity (real frame independent interaction force), you have to introduce an inertial force to make Newton's 2nd Law work in a free falling frame.
The only difficulty here is: how do you determine that there is a force of gravity? There is no experiment that you can do to measure the gravitational force.

If you were in a capsule being hurled around a centrifuge (unbeknownst to you), treating your non-inertial frame as inertial, you would have to postulate some force of unknown origin pulling things outward. You could measure these forces using a spring, for example.

If you were in a charged capsule being accelerated in the direction of an oppositely charged body and treating your non-inertial frame of reference as if it were inertial, you could do a local experiment and you would conclude that non-charged bodies moved differently than charged bodies so you would have to postulate mysterious forces that were like electrical forces except that they operated on non-charged bodies and acted differently, or not at all, on charged bodies.

But if the accelerating force is a locally uniform gravitational force (which you have no means of detecting if you treat your non-inertial frame as inertial) there is no need for additional forces in order to make Newton's laws of motion work in your free-falling frame of reference.

As far as GR is concerned, is this not just another way of looking at the principle of equivalence? Frames of reference accelerating in a locally uniform gravitational field do not require fictitious (inertial) forces in order to apply the laws of motion.

AM
 
  • #32
Andrew Mason said:
how do you determine that there is a force of gravity?
Newton's law of universal gravitation tells you so.

Andrew Mason said:
there is no need for additional forces in order to make Newton's laws of motion work in your free-falling frame of reference.
If you don't use Newton's version of gravitation. That's what GR does, where the free falling frame is considered locally inertial.
 
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  • #33
Andrew Mason said:
??. But that is my point. One does not need to introduce inertial forces in order to make Newton's laws work in a non-inertial frame where the acceleration is caused by gravity.
Andrew Mason said:
treating your non-inertial frame as inertial
Andrew Mason said:
There is no experiment that you can do to measure the gravitational force.
If you have a frame that is experimentally indistinguishable from inertial, why are you calling it non-inertial?
 
  • #34
A.T. said:
Newton's law of universal gravitation tells you so.
How can the observer in the free-falling frame apply Newton's law of universal gravitation if he can't detect gravity?

AM
 
  • #35
Andrew Mason said:
How can the observer in the free-falling frame apply Newton's law of universal gravitation if he can't detect gravity?
If the frame is "non-inertial" due to gravity then you have stipulated that gravity exists whether it is detected or not. There's no sense quibbling about what you've already stipulated to.

In any case, a free falling observer can easily detect gravity. He looks around at the other free falling objects. [This does not count against the equivalence principle since such observations are non-local]
 
  • #37
A.T. said:
By plugging numbers into the formula:
https://en.wikipedia.org/wiki/Newton's_law_of_universal_gravitation#Modern_form
As you see the force is independent of reference frame (observer).
Your means of determining the mass of the gravitating object is to use M = r^2g/G where r is the distance to the centre of mass of M and g is your acceleration toward the common centre of mass. But our premise is that the frame of reference of the spacecraft is treated as an inertial frame for applying the laws of physics, so it is not accelerating.

I think that all we can say is that inertial forces do not arise in a frame of reference that is undergoing gravitational free fall in a locally uniform gravitational field and that this is not the case with any other force. Why it is an exception is something that Einstein explores in the General Theory of Relativity. jbriggs asks the right question: "If you have a frame that is experimentally indistinguishable from inertial, why are you calling it non-inertial?"

AM
 
  • #39
Andrew Mason said:
The force is independent of which inertial frame in which it is measured.
Newtonian gravity is independent of reference frame, regardless whether inertial or not.

Andrew Mason said:
But our premise is that the frame of reference of the spacecraft is treated as an inertial frame
That's the GR interpretation, not your premise under Newtonian gravity. Read you own post #26.
 
  • #40
A.T. said:
Newtonian gravity is independent of reference frame, regardless whether inertial or not.
That would mean that acceleration measured in a noninertal frame will be the same as measured in an inertial frame...?

That's the GR interpretation, not your premise under Newtonian gravity. Read you own post #26.
??The whole point is to apply the laws of physics in a noninrtial frame. If the body is undergoing constant acceleration due to gravity, one can apply Newton's laws without having to posit some non-Newtonian force.

AM
 
  • #41
Andrew Mason said:
That would mean that acceleration measured in a noninertal frame will be the same as measured in an inertial frame...?
The acceleration measured in a non-inertial frame is different from the acceleration measured in an inertial frame. If one accepts Newton's second law, the net force in a non-inertial frame is different from the net force in an inertial frame. The delta is an inertial force associated with the choice of a non-inertial frame.

If you consider a freely falling frame to be non-inertial then Newtonian gravity is not that inertial force.

??The whole point is to apply the laws of physics in a noninrtial frame. If the body is undergoing constant acceleration due to gravity, one can apply Newton's laws without having to posit some non-Newtonian force.
But that is not the situation that you are positing in post #26. You are positing an object that is NOT undergoing constant acceleration due to gravity. Rather, you are positing an object that is stationary in a "non-inertial frame" [your words] in spite of gravity. This demands some non-Newtonian force to keep it in place.
 
  • #42
jbriggs444 said:
The acceleration measured in a non-inertial frame is different from the acceleration measured in an inertial frame. If one accepts Newton's second law, the net force in a non-inertial frame is different from the net force in an inertial frame. The delta is an inertial force associated with the choice of a non-inertial frame.

If you consider a freely falling frame to be non-inertial then Newtonian gravity is not that inertial force.
I agree.. One does not need to assume any non-Newtonian forces in order to make Newton's laws of motion work.
But that is not the situation that you are positing in post #26. You are positing an object that is NOT undergoing constant acceleration due to gravity. Rather, you are positing an object that is stationary in a "non-inertial frame" [your words] in spite of gravity. This demands some non-Newtonian force to keep it in place.
In post 26 I refer to a free-falling or orbiting spacecraft . Perhaps you mean some other post. If a body is stationary in the non-inertial frame of that spacecraft there is no need to posit any non-Newtonian force to keep it in place. That is all I am saying.

AM
 
  • #43
Andrew Mason said:
That would mean that acceleration measured in a noninertal frame will be the same as measured in an inertial frame...?
No, it doesn't mean that.
 
  • #44
Andrew Mason said:
The only difficulty here is: how do you determine that there is a force of gravity? There is no experiment that you can do to measure the gravitational force.

AM
If we are working in the context of Newtonian gravity (not GR), then you determine that there is a force of gravity by looking outside the craft and observing the planet below. Then you deduce that you should be falling toward it but you are not, and therefore you have to postulate (in your frame a reference) an imaginary force keeping you from falling.
 
  • #45
nrqed said:
If we are working in the context of Newtonian gravity (not GR), then you determine that there is a force of gravity by looking outside the craft and observing the planet below. Then you deduce that you should be falling toward it but you are not, and therefore you have to postulate (in your frame a reference) an imaginary force keeping you from falling.

The difference between a spacecraft i) being hurled around in a centrifuge on the one hand and ii) being in gravitational orbit is that the observer can detect and measure the force (that the inertial observer views as centripetal) in i) but cannot measure that force in ii). In the case of i) he can measure tensions - i.e. the force required to keep an object stationary. In the second case, no force is required to keep an object stationary. We could suppose, for example that the gravitating mass is an invisible black hole or dark matter - ie. the observer would not be able to tell that he is subjected to a gravitational force. No inertial forces would have to be postulated in order to make Newton's laws of motion work in that frame of reference.

AM
 
  • #46
Andrew Mason said:
The difference between a spacecraft i) being hurled around in a centrifuge on the one hand and ii) being in gravitational orbit is that the observer can detect and measure the force (that the inertial observer views as centripetal) in i) but cannot measure that force in ii). In the case of i) he can measure tensions - i.e. the force required to keep an object stationary. In the second case, no force is required to keep an object stationary. We could suppose, for example that the gravitating mass is an invisible black hole or dark matter - ie. the observer would not be able to tell that he is subjected to a gravitational force. No inertial forces would have to be postulated in order to make Newton's laws of motion work in that frame of reference.

AM
Well, if I would put Newton in the ISS, he would know that there is a face of gravity because of the presence of the planet, do you agree??
The situation is not different from being in a centrifuge. If I have a plumb line in a centrifuge, I know there is a tension force pulling one way and therefore I may invent the concept of centrifugal force to explain what happens. If I am in the space station, I know there is a force of gravity pulling one way and therefore I may invent a force to explain why objects seem to be floating around in my frame. You are saying that because I don't see anything physical acting on an object, because it is gravity which seems to act a distance (in Newtonian gravity), I can ignore it. I would think that Newton would have disagreed.
 
  • #47
Andrew Mason said:
We could suppose, for example that the gravitating mass is an invisible black hole or dark matter - ie. the observer would not be able to tell that he is subjected to a gravitational force. No inertial forces would have to be postulated in order to make Newton's laws of motion work in that frame of reference.
Newtonian inertial frames extend to infinity, and aren't limited by what some person can see. Newton's laws of motion do not hold throughout that frame, so it's not inertial.
 
  • #48
nrqed said:
Well, if I would put Newton in the ISS, he would know that there is a face of gravity because of the presence of the planet, do you agree??
Yes. But then he knows that he is accelerating and that defeats the premise (that he thinks of his non-inertial frame as inertial). You might as well use the example of a person in an accelerating car and say that he knows that the trees and buildings that are fixed to the Earth are passing by at an accelerated rate and must conclude that he is accelerating. The point is that he is not supposed to know what is actually happening. He is supposed to make Newton's laws of motion work in his frame of reference while being oblivious to the fact that his frame is non-inertial. To do that he has to invent an inertial force.

AM
 
  • #49
Andrew Mason said:
The point is that...
Do you actually have a point, that goes beyond what the Equivalence Principle states? Because I don't think that anybody here argues against the EP, just against your confused description.
 
  • #50
Andrew Mason said:
Yes. But then he knows that he is accelerating and that defeats the premise (that he thinks of his non-inertial frame as inertial). You might as well use the example of a person in an accelerating car and say that he knows that the trees and buildings that are fixed to the Earth are passing by at an accelerated rate and must conclude that he is accelerating.

AM
I think you are missing the point about non inertial frames. How would you convince someone that he is accelerating? You say that you can just point out to the trees moving by with a relative acceleration and that shows that one is accelerating. But that is not the point! The person in the car could say "actually, I think it is the trees of that are accelerated past me, while I am at rest (or moving at constant velocity). Maybe I am in a huge hangar and my car is immobile while you are rolling past me a huge carpet with trees past me! *That* is the point: how does one disprove that? And the answer is that if one tries to apply Newton's laws, the only way to make it work is to introduce fictitious forces to make F =ma work in the frame of the car, and *this* is what shows that the car is accelerating, *not* that trees are accelerating by!

Now, in the case of the space shuttle, the situation is the same: one knows that there is a planet nearby (in order to make any statement about forces, one must be given information about the system in which one is. If you close the eyes of someone and give them no information whatsoever about their surroundings, there is no way to discuss anything regarding frames in classical physics). Now, given that there is a planet nearby, the person knows that he/she is attracted to it. So the only way to stay in orbit is to either introduce a fictitious force in the non inertial frame to make Newton's laws work or to realize that since the frame is non inertial, Newton's laws are not valid in that frame.
 
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