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Quick probability question

  1. Jun 28, 2008 #1
    Let's say you have 100 marbles in a jar, one of them is unique. The chances of that "one" being picked would be 1/100 or 1%.


    Now let's say you picked a handful of marbles, 16 at a time, what would be the probability that that unique "one" would get picked again?

    My guess is 100/16 = 6.25, and then 1/6.25 or 16%. Is this correct?

    What would the technical term for this type of grouping probability be?


    thanks!
     
  2. jcsd
  3. Jun 28, 2008 #2

    HallsofIvy

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    Well, if you kept the unique one in your hand after picking it the first time, the probability is 0! So I am going to assume that the "unique" marble has been replaced. This is called "sampling with replacement".

    Strange way to do that calculation. Why not just 16/100?

    The probability that specific marble will be picked on any one trial is 1/100 and the probability that some other marble will be picked in 99/100. If you pick 16 marbles, the probability that specific marble will be a specific one (if you set all 16 in a row, the probability is will be, say, the 9th marble in the row) will be (1/100)(99/100)15= 9915/10016. But there are 16 different such positions so the probability the unique marble will be somewhere in that group of 16 is (16)(9915/10016= 0.1376 or about 13.76%.
     
  4. Jun 28, 2008 #3
    Hey HallsofIvy thank you for the reply. I have never done one thing with probabilities before. As i read more about them online most examples are pretty simple but some I don't understand. I guess I was thinking about it in a weird direction, either way I am going to have to look at that last paragraph you wrote it is slightly confusing.


    thanks
     
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