Quick question about exponential and logarithms

[rlm42]

If I have ln(e^(-8.336/10c)) wouldn't that be the same as ln(e^(1/(8.336/10c))) therefore = 1/(8.336/10c) = 10c/8.336? I am confused about this because in my lecture notes they simplified ln(e^(-8.336/10c)) to just = -8.336/10c

Your help would be appreciated!

 

[chiro]

Hey rlm42 and welcome to the foums.

If you let x = -8.336/10c and use the fact that e^(ln(x)) = ln(e^(x)) = x then it means that

ln(e^(x)) = x = ln(e^(-8.336/10c)) = -8.336/10c.

All I'm doing is replacing a complex variable with a simple variable and using the identities for logarithms and exponentials.

 

[rlm42]

nvm thnaks!

 

[SteamKing]

e^(-a) = 1/(e^a) not e^(1/a). There is a difference.