Quick question about Oribtal Velocities

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SUMMARY

The discussion centers on the work-energy theorem as it applies to elliptical orbits, specifically regarding the relationship between work done and kinetic energy (KE). It is established that for a body moving from point A to point B in an elliptical orbit, the total work done by gravitational force equals the change in kinetic energy. The gravitational potential energy is not included in this calculation to avoid double counting, as it is defined as the negative work done by gravity.

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Homework Statement



I was reading in a book a little section about orbital velocities.

It states:

For elliptical orbits, consider a body moving from point A to point B. The total work done by the force on the body is given by

W = KE (for B) - KE (for A)

Homework Equations


The Attempt at a Solution



Since W=Fd, does the KE simply represent the kinetic energy?

Thank you.
 
Last edited:
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Hi ZedCar! :smile:

Yes, the work energy theorem says that the change in energy equals the work done.

Since the only energy that changes for an orbiting body is the kinetic energy, and the only force is gravity, that means the change in kinetic energy equals the work done by gravity.

(We ignore the gravitational potential energy, since it is defined as minus the work done by a conservative force, such as gravity … and we cannot count it twice! :wink:)
 

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