Yes, I know what you're talking about. It depends whether the factors in the denominator are linear factors or irreducible quadratic factors.
For example, with 3/[(x - 1)(x2 + 1)], the x - 1 factor in the denominator is a linear factor (x is to power 1) and x2 + 1 is an irreducible quadratic. The decomposition would look like this:
3/[(x - 1)(x2 + 1)] = A/(x - 1) + (Bx + C)/(x2 + 1)
To reduce 3/[(x - 1)(x - 2)], both factors in the denominator are linear factors, so the decomposition would look like this:
3/[(x - 1)(x - 2)] = A/(x - 1) + B/(x - 2)
If you have repeated linear factors, such as 5/[(x - 1)2, things are a little different and the decomposition would be this:
5/[(x - 1)2 = A/(x - 1) + B/(x - 1)2
Hope that helps.