- #1

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## Homework Statement

lim (root*(6-x) -2)/(root*(3-x)-1)

x->2

## Homework Equations

i know in a normal limit if a square root was on the top of bottom, you would multiply it and so on so on.....but the fact that there is a square root on the top and the bottom is throwing me off.

## The Attempt at a Solution

again, i multiplied the top and bottom by root*(6-x) +2/root*(6-x) +2....then thats as far as i get