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Quick question on limits involving square roots

  1. Nov 13, 2008 #1
    1. The problem statement, all variables and given/known data

    lim (root*(6-x) -2)/(root*(3-x)-1)
    x->2

    2. Relevant equations

    i know in a normal limit if a square root was on the top of bottom, you would multiply it and so on so on.....but the fact that there is a square root on the top and the bottom is throwing me off.

    3. The attempt at a solution

    again, i multiplied the top and bottom by root*(6-x) +2/root*(6-x) +2....then thats as far as i get
    1. The problem statement, all variables and given/known data



    2. Relevant equations



    3. The attempt at a solution
     
  2. jcsd
  3. Nov 13, 2008 #2

    tiny-tim

    User Avatar
    Science Advisor
    Homework Helper

    Hi banfill_89! :smile:

    (have a square-root: √ :wink:)
    So you got 2 - x on the top, and nasty square-roots on the bottom …

    so apply l'Hôpitals' rule! :wink:
     
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