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Quick question on limits involving square roots

  • Thread starter banfill_89
  • Start date
  • #1
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Homework Statement



lim (root*(6-x) -2)/(root*(3-x)-1)
x->2

Homework Equations



i know in a normal limit if a square root was on the top of bottom, you would multiply it and so on so on.....but the fact that there is a square root on the top and the bottom is throwing me off.

The Attempt at a Solution



again, i multiplied the top and bottom by root*(6-x) +2/root*(6-x) +2....then thats as far as i get

Homework Statement





Homework Equations





The Attempt at a Solution

 

Answers and Replies

  • #2
tiny-tim
Science Advisor
Homework Helper
25,832
251
Hi banfill_89! :smile:

(have a square-root: √ :wink:)
lim (root*(6-x) -2)/(root*(3-x)-1)
x->2

again, i multiplied the top and bottom by root*(6-x) +2/root*(6-x) +2....then thats as far as i get
So you got 2 - x on the top, and nasty square-roots on the bottom …

so apply l'Hôpitals' rule! :wink:
 

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