Quick question on Special Relativity

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SUMMARY

The discussion confirms the calculations regarding the travel time of a spacecraft to Alpha Centauri, located 4 light years away, when traveling at 0.8c. The spacecraft experiences length contraction, perceiving the distance as 2.4 light years, resulting in a travel time of 3 years in its reference frame. Due to time dilation, an observer on Earth measures 5 years passing during the journey, consistent with the calculation of t = d/v = 4/0.8. All calculations presented are accurate and validated.

PREREQUISITES
  • Understanding of Special Relativity concepts such as time dilation and length contraction.
  • Familiarity with the formula for calculating time based on distance and velocity (t = d/v).
  • Knowledge of the speed of light (c) and its significance in relativistic physics.
  • Basic understanding of reference frames in physics.
NEXT STEPS
  • Study the implications of time dilation in high-speed travel scenarios.
  • Explore the concept of length contraction in different reference frames.
  • Learn about the Lorentz factor (gamma) and its role in relativistic calculations.
  • Investigate practical applications of Special Relativity in modern physics and technology.
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Students of physics, educators teaching relativity, and anyone interested in the implications of high-speed travel in the context of Special Relativity.

hmvince
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Just to make sure I'm doing things right:
Alpha Centauri is located 4 light years away. A spacecraft travels at 0.8c towards this star, as seen from earth. How long will the spacecraft take to reach its destination?

The spacecraft sees the distance to Alpha Centauri as 2.4 light years due to length contraction.
This means that the spacecraft will reach Alpha Centauri in:
t = d/v = 2.4/0.8 = 3 years ( spacecraft s reference frame)

Then, because of time dilation, the observer on Earth sees:
3 * gamma = 5 years go by.

This then matches up with:
t = d/v = 4/0.8 = 5 years (according to Earth's observer).

Is this all correct?
 
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