Quick question on the logarithim property

  • Thread starter vorcil
  • Start date
  • #1
395
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If i were to simplify

[tex] ln(c*e^{-kt}) [/tex]

what happens?

do I get

[tex] c*(-kt) [/tex]
or
[tex] ln(c) * (-kt) [/tex]

or something else?

I'm not sure
 

Answers and Replies

  • #2
Dick
Science Advisor
Homework Helper
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Neither. log(a*b)=log(a)+log(b). Start with that.
 
  • #3
395
0
Neither. log(a*b)=log(a)+log(b). Start with that.

Cheers big ears,
 
  • #4
1,097
3
[tex]ln(AB) = ln(A) + ln(B)[/tex]

Does that help?

EDIT:
Neither. log(a*b)=log(a)+log(b). Start with that.

You beat me to it!
 

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