- #1

- 395

- 0

[tex] ln(c*e^{-kt}) [/tex]

what happens?

do I get

[tex] c*(-kt) [/tex]

or

[tex] ln(c) * (-kt) [/tex]

or something else?

I'm not sure

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- Thread starter vorcil
- Start date

- #1

- 395

- 0

[tex] ln(c*e^{-kt}) [/tex]

what happens?

do I get

[tex] c*(-kt) [/tex]

or

[tex] ln(c) * (-kt) [/tex]

or something else?

I'm not sure

- #2

Dick

Science Advisor

Homework Helper

- 26,263

- 619

Neither. log(a*b)=log(a)+log(b). Start with that.

- #3

- 395

- 0

Neither. log(a*b)=log(a)+log(b). Start with that.

Cheers big ears,

- #4

- 1,097

- 3

Does that help?

EDIT:

Neither. log(a*b)=log(a)+log(b). Start with that.

You beat me to it!

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