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Quick question on the logarithim property

  1. Aug 4, 2010 #1
    If i were to simplify

    [tex] ln(c*e^{-kt}) [/tex]

    what happens?

    do I get

    [tex] c*(-kt) [/tex]
    [tex] ln(c) * (-kt) [/tex]

    or something else?

    I'm not sure
  2. jcsd
  3. Aug 4, 2010 #2


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    Neither. log(a*b)=log(a)+log(b). Start with that.
  4. Aug 4, 2010 #3
    Cheers big ears,
  5. Aug 4, 2010 #4
    [tex]ln(AB) = ln(A) + ln(B)[/tex]

    Does that help?

    You beat me to it!
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