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__Question__The α-emitter 210, 84 Po is used in a nuclear battery. The kinetic energy of the emitted alpha particles can be worked out from energy and momentum conservation. It is converted into electrical energy at 5.0% efficiency.

(a) Determine the initial power output (in W) of the battery if it contains 320 g of 210, 84 Po. Look "www.google.com/search?hl=en&q=210+Po+nuclear+decay"[/URL] (for instance) for relevant data.

(b) Determine the power output (in W) of the battery in (a) after 1 year of operation.

[RIGHT][8 marks][/RIGHT]

[U][B]Answer[/B][/U]

not sure if anyone agrees with me on this one, but this work is worth 40% of the entire module and they have the cheek to link me to a google search and effectively tell me to find all the necessary values myself, i wasn't impressed...especially when you think that you might have the knowledge to do the question and just not know where to find reliable values from...

anyway on with my answer

(a) well i would firstly use [B]kinetic energy = 1/2 mv[SUP]2[/SUP][/B] where m=mass of an alpha particle and v=emission speed then times that by amount emitted per second (activity) to get an answer in joules per second (ie Watts) then times by 0.05 for an efficiency factor of 5%

(b) find the half life of 210, 84 Po and use [B]N = N[SUB]0[/SUB] e[SUP]-[tex]\lambda[/tex] t[/SUP][/B] to find the number of nucleons left after one year then use [B]R=[tex]\lambda[/tex] N[/B] for the activity after one year, then simply repeat the method for question (a)...

i appreciate that these might be the right methods but i posted this in order to give you an idea of what values i'm searching for, if im wrong in the solutions above please say.

any feedback would be much appreciated, thanks guys

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