Radioactivity and radioactive decay

AI Thread Summary
The discussion revolves around calculating the remaining percentage of thorium after 266 days, given its half-life of 1.913 years. The user initially attempted to find the solution using the atomic mass but encountered errors in their calculations. They realized that since 266 days is less than the half-life, more than 50% of thorium should remain. The correct approach involves using the formula N=No*(1/2)^n, where n represents the number of half-lives. Ultimately, the user confirmed their understanding and arrived at the correct solution.
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[SOLVED] Radioactivity and radioactive decay

Homework Statement


Thorium (with half-life T1/2 = 1.913 yr. and atomic mass 228.028715 u) undergoes alpha decay and produces radium (atomic mass 224.020186 u) as a daughter nucleus. (Assume the alpha particle has atomic mass 4.002603 u.)

What percent of thorium is left after 266 days?



Homework Equations



X --> Y + He
N=No*(1/2)^n
n= t/T(half)
T(half)= .693/\lambda


The Attempt at a Solution



I found that lambda=4.14x10^-5 hrs^-1 (the problem asks for it in hours, dumb, I know.)

I then found the number of half-lives to be 266 days, or 6384 hours divided by 16757.88 hours, to be .381 half-lives. I multiplied this by Thorium's atomic mass to get 36% but this keeps turning up incorrect for my online homework.
 
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Why don't you just apply N=No*(1/2)^n ?

since 266 days is shorter than the half life, more than 50% should be left.
 
Ahhhhh for some reason I thought I needed to now the number of nuclei, did NOT know I could just use the atomic mass. I got it, thank you!
 
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