Radium decomposes radioactively

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Radium decomposes radioactively to form radon (atomic number 86, which is also the number of protons in the nucleus) by emitting an alpha-particle from its nucleus.

The mass of an alpha-particle is 6.6404 x 10^-24 grams.

What is the force of repulsion between the radon nucleus and the alpha-particle, when the distance between them is 5 x 10^-11 cm?

What is the acceleration of the alpha-particle at this distance?

I am not sure what equation I need to use to solve this equation.

Any help would be appreciated!
 
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Try looking up Coulomb's law.
 
Coulomb's law is F = k x ((force1 x force2)/r^2)

Where k is 8.99 x 10^9

and r = distance between them which is 5 x 10^-11

I do not know how to get the force of each particle.

Some more help would be appreciated!
 
EsKiMoMoNKeY said:
Coulomb's law is F = k x ((force1 x force2)/r^2)

Where k is 8.99 x 10^9

and r = distance between them which is 5 x 10^-11

I do not know how to get the force of each particle.

Some more help would be appreciated!

No, that's not Coulomb's law. Coulombs law is
Force = k x ((charge1 x charge2)/r^2)
 
So i do not know what the alpha-particles charge is, but i can look up radon's charge right?

EDIT
So the alpha-particle's charge is the opposite of what radium loses?
 
Last edited:
Do you know what an alpha particle is? You should be able to look up its charge also.
 
The entire question was in my first post. The difference between radium to radon is 88 -> 86 so would charge 1 be 2 and charge 2 be -2?
 
No. You should know or be able to find:

(1) What is the charge on a Radon nucleus?
(2) What is an alpha particle and what is its charge?
 
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