Radius of convergence problem

In summary, we are looking for an expansion of the rational function f(x,z)=z/(x^z-1) that is valid for all positive real values of x and complex values of z. We can use a Bernoulli-type expansion, but it is only valid for |zlnx|<2π. To find a more general expansion, we consider an expansion around z=1 of the form f(z,x)=∑f_n(x)(z−1)^n, where f_n(x) are suitable functions in x that ensure convergence. The first two functions are given by f0(x)=1/(x−1) and f1(x)=(x−xlnx−1)/(x−1)^2
  • #1
mmzaj
107
0
consider the rational function :

[tex]f(x,z)=\frac{z}{x^{z}-1}[/tex]
[tex]x\in \mathbb{R}^{+}[/tex]
[tex]z\in \mathbb{C}[/tex]

We wish to find an expansion in z that is valid for all x and z. a Bernoulli-type expansion is only valid for :
[tex] \left | z\ln x \right |<2\pi[/tex]
Therefore, we consider an expansion around z=1 of the form :
[tex] \frac{z}{x^{z}-1}=\sum_{n=0}^{\infty}f_{n}(x)(z-1)^{n}[/tex]
Where [itex] f_{n}(x)[/itex] are suitable functions in x that make the expansion converge. the first two are given by :
[tex] f_{0}(x)=\frac{1}{x-1}[/tex]

[tex] f_{1}(x)=\frac{x-x\ln x -1}{(x-1)^{2}}[/tex]
now i have two questions :
1-in the literature, is there a similar treatment to this specific problem !? and under what name !?
2- how can we find the radius of convergence for such an expansion !?
 
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  • #2
it's not so hard to prove that the functions [itex]f_{n}(x) [/itex] have the general form :
[tex]f_{n}(x)=\frac{(-\ln x)^{n-1}}{n!}\left(n\text{Li}_{1-n}(x^{-1})-\ln x\;\text{Li}_{-n}(x^{-1})\right) [/tex]
 
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1. What is the radius of convergence for a power series?

The radius of convergence for a power series is the distance from the center of the series to the nearest point where the series converges. It is represented by the variable "R" and is typically found by using the ratio test or the root test.

2. How do you determine the radius of convergence for a specific power series?

To determine the radius of convergence for a specific power series, you can use the ratio test or the root test. These tests involve taking the limit of the absolute value of the ratio or root of the coefficients of the series. If the limit is less than 1, the series will converge within a certain radius. If the limit is greater than 1, the series will diverge. If the limit is equal to 1, the test is inconclusive and another method must be used.

3. What is the significance of the radius of convergence?

The radius of convergence is significant because it determines the interval of convergence for a power series. This means that the series will only converge for values of the variable within this interval. Beyond this interval, the series will diverge.

4. Can the radius of convergence be negative?

No, the radius of convergence cannot be negative. It is a distance and therefore must be a positive value. However, the interval of convergence can include negative values depending on the specific power series.

5. How does the radius of convergence impact the accuracy of a power series approximation?

The closer the value of the variable is to the center of the series (within the radius of convergence), the more accurate the approximation will be. As the value of the variable moves further away from the center, the accuracy of the approximation decreases and the series may even diverge. This is why it is important to determine the radius of convergence before using a power series as an approximation for a specific value.

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