Raising and Lowering momentum operators

soul
Messages
61
Reaction score
0
10nrx1w.jpg


I tried to use the eigenvalue of the operators but I couldn't get the result.
Can anyone help me to understand this relationship?

Thank you.
 
Physics news on Phys.org
if you multiply out the brackets inside the square root, you will find that they are in fact the eigenvalues of the L+ and L- operators.

Remember that L+|l,m2> = Eigenvalue*|l,m2+1>

Once you have operated with L+ on the left hand side you can move the eigenvalue out to the front as it is just a number. You are left with:

<l,m1|l,m2+1>, which, by orthogonality, is 0 unless m1 = m2+1. This is precisely what the dirac delta functions on the right hand side represent.
 
Hi, I had an exam and I completely messed up a problem. Especially one part which was necessary for the rest of the problem. Basically, I have a wormhole metric: $$(ds)^2 = -(dt)^2 + (dr)^2 + (r^2 + b^2)( (d\theta)^2 + sin^2 \theta (d\phi)^2 )$$ Where ##b=1## with an orbit only in the equatorial plane. We also know from the question that the orbit must satisfy this relationship: $$\varepsilon = \frac{1}{2} (\frac{dr}{d\tau})^2 + V_{eff}(r)$$ Ultimately, I was tasked to find the initial...
The value of H equals ## 10^{3}## in natural units, According to : https://en.wikipedia.org/wiki/Natural_units, ## t \sim 10^{-21} sec = 10^{21} Hz ##, and since ## \text{GeV} \sim 10^{24} \text{Hz } ##, ## GeV \sim 10^{24} \times 10^{-21} = 10^3 ## in natural units. So is this conversion correct? Also in the above formula, can I convert H to that natural units , since it’s a constant, while keeping k in Hz ?
Back
Top