Range of f(x): Find Max & Min Value with f'(x)

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SUMMARY

The discussion focuses on determining the range of the function f(x) = ln(-x² + x + 6) by utilizing its derivative f'(x). The maximum value of the range is easily identified by setting the derivative to zero, while the minimum value is confirmed to be negative infinity as the function approaches the boundaries of its domain, which is between -2 and 3. Participants agree that as x approaches -2 from above or 3 from below, the function approaches zero from above, reinforcing that the lower limit of the range is indeed negative infinity.

PREREQUISITES
  • Understanding of natural logarithmic functions
  • Knowledge of calculus, specifically derivatives
  • Familiarity with domain restrictions in functions
  • Ability to analyze limits and behavior of functions at boundaries
NEXT STEPS
  • Study the properties of natural logarithmic functions
  • Learn how to compute and interpret derivatives
  • Explore limit concepts in calculus, particularly one-sided limits
  • Investigate the implications of domain restrictions on function behavior
USEFUL FOR

This discussion is beneficial for students and educators in calculus, mathematicians analyzing logarithmic functions, and anyone interested in understanding the behavior of functions within specified domains.

fiziksfun
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Let f(x)= ln(-x^2+x+6)

Find the range of f(x). Use f'(x) to support your answer.

Attempt at a solution:

Find the max. value of the range is easy. I found the derivative and set it equal to zero. My REAL PROBLEM is finding the minimum value of the range.

The function's domain must be between -2 and 3 becus you cannot take the natural lg of a negative number or zero.
SO, as f(x) approaches, 3 or -2, does it approach negative infinity??
Am I right when I say its lower range is negative infinity?? HELP!
 
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As x approaches -2 from above or 3 from below, then -x^2+x+6 approaches 0 from above. So yes, you are right.
 

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