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Range problem

  1. Oct 9, 2005 #1
    f(x)=5^sqrt(2(x^2)-1)

    I got that range is (1, to infinity)

    Is it correct?
     
  2. jcsd
  3. Oct 9, 2005 #2

    Fermat

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    What does f equal if x = -2 ?
     
  4. Oct 9, 2005 #3
    5^sqrt(7). If x=sqrt(2)/2, then I get F(x)=1
     
  5. Oct 9, 2005 #4
    Isn't x= sqrt(1/2) the lowest you can go?
     
  6. Oct 9, 2005 #5

    Fermat

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    By range, do you mean the range of x-values or y-values ?

    If it's for the y-values then your range of 1 - infinity is correct.

    If it's for the x-values, then that's a bit different.
     
  7. Oct 9, 2005 #6
    For y values. They teach us to call x-values domain.
     
  8. Oct 10, 2005 #7

    Fermat

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    That's right.
    I use domain for x-values and co-domain for y-values.
    But i've seen range used for x-values before.
     
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