Ranking brightness of lightbulbs in a circuit

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SUMMARY

The discussion clarifies the brightness ranking of lightbulbs in a circuit where lightbulb A is in parallel with lightbulbs B and C. Lightbulb A is the brightest because it experiences a higher voltage drop compared to B and C, which share the voltage equally. The power for B and C is equal but lower than that of A due to the voltage drop being halved across each of them. This conclusion is based on the principle that lightbulbs in parallel have the same voltage across them.

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  • Knowledge of Ohm's Law and power calculations (P = I * V)
  • Familiarity with series and parallel circuit configurations
  • Basic concepts of voltage drop in electrical circuits
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ikihi
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Homework Statement



In the circuit shown, all the light bulbs are the same. Why is the following statement true? :

A is the brightest. B and C are equally bright, but are dimmer than A.


https://pbs.twimg.com/media/C6GllsQVMAA4chz.jpg:large
https://twitter.com/FauxNews101/status/838133087464640513

Homework Equations



P = I * V

The Attempt at a Solution


[/B]
There is more of a voltage drop across B to C than A, so the power is less for both B and C than A since power is proportional to I and V? Since B and C are the same then they should be the same brightness because they each have the same resistance, in series?
 
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ikihi said:
There is more of a voltage drop across B to C than A,
No. lightbulb A is in parallel with B+C. So the voltage drop across B is half of that across A, and the drop across C is half that across A.

Try again? :smile:
 
berkeman said:
No. lightbulb A is in parallel with B+C. So the voltage drop across B is half of that across A, and the drop across C is half that across A.

Try again? :smile:

The voltage drop of B+C equals the voltage drop of A. This is so because light bulb A equals the voltage drop across the equivalent of B+C since light bulbs in parallel have the same voltage. So B or C has half the voltage that A does; and because of that, the power for B and C is equal, but B or C is less power than A.
 
ikihi said:
The voltage drop of B+C equals the voltage drop of A. This is so because light bulb A equals the voltage drop across the equivalent of B+C since light bulbs in parallel have the same voltage. So B or C has half the voltage that A does; and because of that, the power for B and C is equal, but B or C is less power than A.
Yes, good. :smile:
 
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