Rate of change in distance question

AI Thread Summary
The discussion revolves around a homework problem involving a baseball player running from second to third base and calculating the rate of change in distance from home plate. The player is 6 meters away from third base and running at a speed of 9 m/s. Using the Pythagorean theorem, the player’s distance from home plate is calculated to be approximately 27.66 meters, leading to a derived rate of change of 1.95 m/s. Participants provide feedback on the solution, suggesting simplifications and clarifications in the mathematical expressions used. The conversation concludes with a light-hearted exchange as the student prepares to submit the assignment.
Dr Zoidburg
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Okay, I'm 99% sure I've got the right answer here, but I just wanted to make certain before I send my assignment in. It's the last question and has been bugging me for the last few days until I had an eureka moment just a few minutes back.
(In case you're wondering, I'm doing my studies by correspondence, so other than course notes and textbooks borrowed from the library I have just the internet and my brains (hah!) to aid me)

Homework Statement


A baseball diamond has sides 27m long. A player is running from 2nd to 3rd at a speed of 9m/s. When he is 6m away from 3rd, at what rate is the player's distance from home plate changing at that instant?


The Attempt at a Solution


x = distance from home plate to 3rd = 27m
y = distance from player to 3rd = 6m
z = distance from player to home = 27.66m (using pythagoras)
speed of player is change of y over time: dy/dt = 9m/s

z^{2} - y^{2}= x^{2}
differentiate with respect to time:
d/dzz^{2} - d/dyy^{2}= 0 (since x doesn't change over time)

dz/dt*2z - dy/dt*2y = 0
divide by 2:
z*dz/dt - y*dy/dt = 0
sub the above (z, y, dy/dt) into the equation and solve:
dz/dt = 1.95m/s

If this ain't correct, please tell me quickly as I need to post my assignment off asap!
 
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Hi Dr Zoidburg! :smile:

Yes, that's fine (but a little messy)! :smile:

Try shortening it a bit.

For example, there's no need to define an x (I know it's useful for helping you get to your eureka moment, but once you're there, you can forget it) … just say z² = y² + 729 (or z = √(y² + 729)). :smile:

And
Dr Zoidburg said:
d/dzz^{2} - d/dyy^{2}= 0
doesn't make sense, does it? :rolleyes:
 
yay, got it right! Off to the post office I scurry.

And that other bit just came out poorly due to bad formating. It looks better in my assignment :wink:
 
Dr Zoidburg said:
yay, got it right! Off to the post office I scurry.

:smile: I thought Dr Zoidburg scuttled ? :smile:
 
whoops. you're right there. scuttled. whoop! whoop! whoop!

"Friends, help! A guinea pig tricked me!"
 
I just did a google search for "A guinea pig tricked me",

:biggrin: and got 5370 hits! :biggrin:
 
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