Solve the 300 Three Ounce Hamburger Patty Math Problem with 20% Shrinkage

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To produce 300 three-ounce hamburger patties with a 20% shrinkage, the raw weight of each patty must be calculated. Since a cooked patty weighs 3 ounces, it represents 80% of the raw weight, which is 3.75 ounces. Multiplying the raw weight of one patty by 300 gives a total of 70.31 pounds of hamburger needed. The calculations confirm that the initial estimation aligns with the required output after accounting for shrinkage. This approach effectively resolves the hamburger math problem.
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hi,
Can someone help me with this please.

How much hamburger will it take to make 300 three ounce patties with a 20% shrinkage?
 
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Hint: If you start with X ounces of hamburger, how many ounces of patties do you end up with?
 
Doc Al said:
Hint: If you start with X ounces of hamburger, how many ounces of patties do you end up with?


Please help me clear it am not getting it, sorry. Thanks 4 ur help.
 
If 20% of the original quantity is lost, remaining quantity (in this case 300 3 oz patties) must equal what percentage of the original?
 
Another approach.. If one patty weighs 3oz after 20% shrinkage (assumed from cooking), how much would a raw patty weigh?
now that you have weight of one raw patty, how much would 300 of those weigh? (if they expect an answer in pounds, don't forget to convert units)
 
Doc Al said:
If 20% of the original quantity is lost, remaining quantity (in this case 300 3 oz patties) must equal what percentage of the original?


Thanks Doc Al.
 
Ouabache said:
Another approach.. If one patty weighs 3oz after 20% shrinkage (assumed from cooking), how much would a raw patty weigh?
now that you have weight of one raw patty, how much would 300 of those weigh? (if they expect an answer in pounds, don't forget to convert units)

Thanks quabache,
16 ounces = 1 pound

3 ounce is 80% of 3.75 ounce, so 3.75 ounce = 0.234 pounds.
Therefore, 0.234 pounds * 300 = 70.31 pounds

Am i right, thanks for ur help.
 
you got it!
 
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