Ratio of K. E. of solid cylinder to shell

[Pushoam]

Homework Statement

Homework Equations

The Attempt at a Solution

total kinetic energy of a rigid body = rotational kinetic energy of the body around its center of mass + translational kinetic energy of center of mass

For solid cylinder, total kinetic energy = $\frac { [I = \frac 1 2 mR^2]\omega ^2 } 2 + \frac 1 2 mv^2 = \frac { 3 mv^2} 4;~ v = \omega R$

Similarly for hollow cylinder , total kinetic energy = $mv^2$

So, the correct opinion is (a).

Is this correct?

 

[haruspex]

the correct opinion is (a).

yes.

 

[Pushoam]

Thanks.