Ratio Test for Series Homework: Author's Solution & Attempt at a Solution

Bashyboy
Messages
1,419
Reaction score
5

Homework Statement


I attached a file that includes the author's solution, and some of my work.


Homework Equations





The Attempt at a Solution

 

Attachments

  • problemjpg.jpg
    problemjpg.jpg
    33.4 KB · Views: 1,068
Physics news on Phys.org
Bashyboy said:

Homework Statement


I attached a file that includes the author's solution, and some of my work.


Homework Equations





The Attempt at a Solution


The denominator in the series is not (2n + 1)! It is the product of the odd integers from 1 to 2n + 1.
 
But can't you write that as (2n + 1)! ?
 
No, not at all.
(2n + 1)! = 1 * 2 * 3 * ... * (2n - 1) * (2n) * (2n + 1)

Your expression skips all the even integers.

A simple example is 5! vs. 1 * 3 * 5. Clearly they aren't equal.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...

Similar threads

Replies
4
Views
1K
Replies
4
Views
2K
Replies
1
Views
1K
Replies
4
Views
1K
Replies
2
Views
2K
Replies
6
Views
2K
Back
Top