- #1
Esoremada
- 52
- 0
The function is f(x) = 2x / x3 - 6x2 + 3x + 10
I was taught that any rational function with a numerator of smaller degree than the denominator has a horizontal asymptote at y = 0, which would apply in this case.
This makes sense for the end behaviors because as x approaches +/- ∞, y approaches 0. However, when x = 0, there seems to be no problem solving the equation and ending up with y = 0, which should be impossible since there's an asymptote there. Should my domain include x ≠ 0? Why is this? The equation resolves normally when x = 0, I thought you only needed restrictions to prevent dividing by 0.
I was taught that any rational function with a numerator of smaller degree than the denominator has a horizontal asymptote at y = 0, which would apply in this case.
This makes sense for the end behaviors because as x approaches +/- ∞, y approaches 0. However, when x = 0, there seems to be no problem solving the equation and ending up with y = 0, which should be impossible since there's an asymptote there. Should my domain include x ≠ 0? Why is this? The equation resolves normally when x = 0, I thought you only needed restrictions to prevent dividing by 0.