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Homework Statement
Find an equation of a rational function f that satisfies the given conditions:
vertical asymptotes: x=-3, x=1
horizontal asymptote: y=0
x-intercept: -1; f(0)= -2
hole at x=2
Homework Equations
The Attempt at a Solution
Vertical Asymptotes are (x+3) and (x-1). Also (x-2) because of the hole
(x+1) would go in the numerator because it corresponds with the x-intercept. I'm not sure where f(0)= -2 fits in this. (x+2) goes in the numerator because of the hole.
(x+1)(x-2)/(x+3)(x-1)(x-2)
The answer looks like 6x^2-6x-12/x^3-7x+6 so I'm obviously missing something, but I don't know what.
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