Rational roots - standard form of equation

AI Thread Summary
To convert the equation 4x^2 + 2kx - k = 2x into standard form, subtract 2x from both sides, resulting in 4x^2 + 2kx - 2x - k = 0. This simplifies to 4x^2 + 2(k-1)x - k = 0, allowing for the application of the quadratic formula to check for rational roots. The key step is recognizing the need to move all terms to one side of the equation. Understanding this transformation is essential for further calculations involving the discriminant. The discussion highlights the importance of careful algebraic manipulation in solving quadratic equations.
Janinever
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Hi everybody!

I've hit a blank with regards to this 1 equation on a old exam paper - think I've overloaded myself a bit and just feel a bit like a airhead at the moment!

I understand the actual method and getting to the answer but it starts off with a equation which you then need to get to a standard form to use the formula to check if the roots are rational.

The initial equation is this :

4x^2 + 2kx - k = 2x

Then on the memorandum this is taken to standard form so the info can be substituted into the formula Δ = b^2 - 4ac

the standard form they then write that initial equation in is :

4x^2 + 2(k-1)x-k = 0

How do they get from 4x^2 + 2kx - k = 2x to this 4x^2 + 2(k-1)x-k = 0

The rest I understand entirely. Literally just the above has be scratching my head!

Please help :)

Thank you!
 
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Janinever said:
How do they get from 4x^2 + 2kx - k = 2x to this 4x^2 + 2(k-1)x-k = 0

Sometimes you overlook the obvious answers. Just subtract 2x from both sides.
 
Thank you!
 
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