RC Op Amp phase shifter transfer function/how to get

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SUMMARY

The discussion focuses on deriving the transfer function for an RC phase shifter using an operational amplifier (op-amp). The key concept involves applying the 'golden rule' of ideal op-amps, which states that the voltage at the non-inverting terminal (v+) equals the voltage at the inverting terminal (v-). The user is guided to treat the RC network as a voltage divider, leading to the equations v+ = Vin * Xc/(R + Xc) and Vin = (1/s*C)//(1/s*C + R) for calculating the output phase and voltage.

PREREQUISITES
  • Understanding of operational amplifier fundamentals
  • Knowledge of RC circuits and their behavior
  • Familiarity with complex impedance (Xc) in AC analysis
  • Basic grasp of transfer functions in control systems
NEXT STEPS
  • Study the derivation of transfer functions for RC circuits
  • Learn about the application of the 'golden rules' in op-amp circuits
  • Explore complex impedance and its role in AC circuit analysis
  • Investigate phase shift characteristics in various filter designs
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Electronics engineers, students studying circuit design, and anyone interested in understanding the behavior of RC phase shifters in op-amp applications.

wig44
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Hello,

I am trying to figure out the transfer function for an RC phase shifter:
http://imgur.com/2dnRYn7 (Picture of circuit)

I am not sure how to calculate the output and specifically the phase of the output of this circuit. I understand that I need to consider one of the 'golden rules' of ideal op amps that v+ = v- but I'm unsure of how to consider the voltage going into v+. My knowledge in this area is pretty shaky!

I understand that I cannot just be supplied with the output/phase equation of this circuit and don't want it, but would like some help figuring it out! Can anyone help push me in the right direction?

Thanks for reading.
 
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Simply treat RC as a voltage divider.
v+ = Vin * Xc/(R + Xc) or Vin = (1/s*C)//(1/s*C + R)
 
Last edited:

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