Re-Write Transcendental Function

  • Thread starter Thread starter James_1978
  • Start date Start date
  • Tags Tags
    Function
AI Thread Summary
The discussion revolves around the equation -k_{2} = k_{1}cot(k_{1}R) and the goal of rewriting it as x = -tan(bx). Participants express confusion about simplifying the equation and seek guidance on deriving tan(k_{1}R) from the given cotangent relationship. There are also suggestions on formatting mathematical expressions for clarity, emphasizing the importance of proper notation. Additionally, it is noted that a new thread has been created to address the same problem more effectively. The conversation highlights the challenges of manipulating transcendental functions in mathematical physics.
James_1978
Messages
34
Reaction score
3

Homework Statement



-k_{2} = k_{1}cot(k_{1}R) and rewrite to x = - tan(bx)

Homework Equations



k_{1} = \sqrt{2m(E + V_{o})/ \hbar^{2}} k_{2} = \sqrt{-2mE/ \hbar^{2}} x = \sqrt{-(V_{o} + E)/E}

The Attempt at a Solution



I am unclear how to simplify this equation.[/B]
 
Physics news on Phys.org
James_1978 said:

Homework Statement



-k_{2} = k_{1}cot(k_{1}R) and rewrite to x = - tan(bx)

Homework Equations



k_{1} = \sqrt{2m(E + V_{o})/ \hbar^{2}} k_{2} = \sqrt{-2mE/ \hbar^{2}} x = \sqrt{-(V_{o} + E)/E}

The Attempt at a Solution



I am unclear how to simplify this equation.[/B]
From your equation ##-k_2 = k_1 \cot(k_1R)##, what would you get for ##\tan(k_1R)##?

BTW: do not write ##cot(\cdot)## and ##tan(\cdot)##; these look ugly and can often be hard to read; instead, write ##\cot(\cdot)## and ##\tan(\cdot)##. Ditto for ##\sin##, ##\cos##, ##\ln##, ##\log##, ##\lim##, ##\max##, ##\min##, ##\exp##, etc. You do that by typing "\cot" instead of "cot", etc.

Also, for one-letter subscripts (or superscripts) it is perfectly OK to skip the curly braces, so it works perfectly well to type "k_1" instead of "k_{1}", etc. But, you need braces for sub (super) scripts of more than one character, such as ##x_{12}##.
 
Thread 'Collision of a bullet on a rod-string system: query'
In this question, I have a question. I am NOT trying to solve it, but it is just a conceptual question. Consider the point on the rod, which connects the string and the rod. My question: just before and after the collision, is ANGULAR momentum CONSERVED about this point? Lets call the point which connects the string and rod as P. Why am I asking this? : it is clear from the scenario that the point of concern, which connects the string and the rod, moves in a circular path due to the string...
Back
Top